Answer:
c. 716, 800 J
Explanation:
t = Time taken
u = Initial velocity = 32 m/s
v = Final velocity = 0
s = Displacement = 60 m
a = Acceleration
m = Mass of car = 1400 kg
Work done is given by
The amount of work done to stop the car is 716800 J
The acceleration of the object after 3 seconds of fall is -9.8 m/s².
The given parameters;
- initial velocity of the object, u = 0
- time of motion of the object, t = 3 seconds
Acceleration is the change in velocity per change in time of motion.
The acceleration of the object after 3 seconds of fall is calculated as follows;
- Since the object is in free fall, the object experiences only acceleration due to gravity.
- the magnitude of this acceleration due to gravity is 9.8 m/s²
- the direction of this acceleration is downwards
Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².
Learn more here: brainly.com/question/13197713
