<span>uclear Physicist specializing inoffensive weapons systems - pretty obvious why this would be.
Highway Engineer - again, pretty obvious reasons.</span>
Answer:
V initial = 29.4 m.s²
Explanation:
( Using the laws of motion)
V final = V initial + Acceleration × time
0 = V initial + ( -9.8)(3)
29.4 = V initial
* I took upward as positive that's why I substituted -9.8 *
* for V final we know that at maximum height the ball is not moving thats why is = 0 *
Answer:
Part a)
Time to reach the maximum height is given as
B)
Maximum height of the bullet is
C)
Horizontal range of the bullet is
Part d)
Final velocity of the bullet is v = 600 m/s at 30 degree
Explanation:
A) As we know that velocity of the bullet is
v = 600 m/s
So we have
Now time to reach the maximum height is given as
B) As we know that the object have zero final speed in y direction
C)
Now the horizontal displacement of the object in total time of flight is known as range of projectile
So we have
Part d)
As we know that the final height is same as that of initial So it will strike the ground at same velocity as that of initial velocity
So we have
v = 600 m/s at 30 degree
Clues or evidence
Im pretty sure its evidence though
I believe the correct answer would be "A" energy source.