Answer:


Explanation:
From the question we are told that
Velocity of aircraft 
Engine air intake rate 
Fuel burn rate 
Velocity of exhaust gas 
Generally the Mass change rate of Rocket is mathematically given by



Generally the Trust of the rocket is given mathematically by



Generally the Rocket's delivered power is mathematically given by
Delivered power P



(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 36.46 N, opposite as the motion of the crate.
(b) The net work done on the crate while it is on the rough surface is 23.7 J.
(c) The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.
<h3>Magnitude of net force on the crate</h3>
F(net) = F - μFf
F(net) = 280 - 0.351(92 x 9.8)
F(net) = -36.46 N
<h3>Net work done on the crate</h3>
W = F(net) x L
W = -36.46 x 0.65
W = - 23.7 J
<h3>Acceleration of the crate</h3>
a = F(net)/m
a = -36.46/92
a = - 0.396 m/s²
<h3>Speed of the crate</h3>
v² = u² + 2as
v² = 0.845² + 2(-0.396)(0.65)
v² = 0.199
v = √0.199
v = 0.45 m/s
Thus, the magnitude and direction of the net force on the crate while it is on the rough surface is 36.46 N, opposite as the motion of the crate.
The net work done on the crate while it is on the rough surface is 23.7 J.
The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.
Learn more about work done here: brainly.com/question/8119756
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Answer:
Roughly three quarters of the Sun's mass consists of hydrogen (~73%); the rest is mostly helium (~25%), with much smaller quantities of heavier elements, including oxygen, carbon, neon, and iron. The Sun is a G-type main-sequence star (G2V) based on its spectral class.
Explanation:
Answer:
<em>The canyon is approximately 314 meters away</em>
Explanation:
<u>Speed of Sound</u>
If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.

Where
is the speed of sound and t is half the time we hear our echo.
The speed of sound in m/s can be calculated from the approximate formula in terms of the temperature T in degrees Celsius

We have
, so


Let's compute x, for t=1.8/2=0.9 seconds


The canyon is approximately 314 meters away
They are formed by cooling 0f molten magna on Earth's surface.