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Naddika [18.5K]
3 years ago
14

What is the area of this figure?

Mathematics
2 answers:
Anna71 [15]3 years ago
3 0
Hope this can help you

Tamiku [17]3 years ago
3 0
The answer is 142 ft squared.
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Bogdan [553]

Answer:

you did not even put anything except "HELP PLEASE IM HORRIBLE WILL GIVE BRAIN LIST IF RIGHT"

7 0
2 years ago
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I need some Help please :)
pychu [463]
I think it’s the last one
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3 years ago
BRAINLIEST if correct
Mekhanik [1.2K]
Okay so median is the number in the middle and mean is when you add them all up and divide by how many numbers there are 

<span>20,28,35,40,132 

So 35 is the median 
and the mean is </span>20 + 28 + 35 + 132 + 40 = 255 / 5 = 51

the mean is a better way to represent the data because it does not just pick a number from the set of numbers it calculates the average 
7 0
3 years ago
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft 6 in tall, and the initial velocity of the ball is 40 f
weqwewe [10]

Answer:

t = 0.293 s and 14.52 s

Step-by-step explanation:

The heights of the ball in feet is given by the equation as follows :

S = -2.7t^2+40t+6.5

Where t is the number of seconds after the ball was thrown.

We need to find is the ball 18 ft above the moon's surface.

Put S = 18 ft

-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0

It is a quadratic equation. Its solution is given by :

t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s

So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.

8 0
3 years ago
A crossover trial is a type of experiment used to compare two drugs. Subjects take one drug for a period of time and then switch
zysi [14]

Answer:

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369

df=n-1=7-1=6

p_v =2*P(t_{(6)}

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

Step-by-step explanation:

We have the following info given by the problem

Subject  1 2 3 4 5 6 7

Drug A  6 3 4 5 7 1 4

Drug B  5 1 5 5 5 2 2

x=value for drug A , y = value for drug B

x: 6 3 4 5 7 1 4  

y: 5 1 5 5 5 2 2

We want to verify if the mean response differs between the two drugs then  the system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x = 0

Alternative hypothesis: \mu_y -\mu_x \neq 0

We can begin calculating the difference d_i=y_i-x_i and we obtain this:

d: -1, -2, 1, 0, -2, 1, -2

Now we can calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.714

Now we can find the the standard deviation for the differences, and we got:

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}}=1.38

And now we can calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369

Now we can find the degrees of freedom given by:

df=n-1=7-1=6

We can calculate the p value, since we have a two tailed test the p value is given by:

p_v =2*P(t_{(6)}

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

7 0
3 years ago
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