Answer:
The answer is B) b
Step-by-step explanation:
According to the Trapezoid area formula, the area of the trapezoid is [(2d+a+b) × c] ÷ 2, however the area also equals (d+b) × c.
So d+(a+b)/2=d+b
(a+b)/2=b
a+b=2b
a=b
hope this helps <3
f(g(x)) is a composite function:
![f(g(x))=f(\sqrt{x+5})=2\sqrt{x+5}-1](https://tex.z-dn.net/?f=f%28g%28x%29%29%3Df%28%5Csqrt%7Bx%2B5%7D%29%3D2%5Csqrt%7Bx%2B5%7D-1)
Plug in <em>x</em> = 4:
![f(g(4)) = 2\sqrt{4+5}-1=2\sqrt9-1=2\cdot3-1=\boxed{5}](https://tex.z-dn.net/?f=f%28g%284%29%29%20%3D%202%5Csqrt%7B4%2B5%7D-1%3D2%5Csqrt9-1%3D2%5Ccdot3-1%3D%5Cboxed%7B5%7D)
so the answer is C.
Answer:
The answer is below
Step-by-step explanation:
From the graph, we can see that both segment 1 and segment 2 are positive slopes (as the time increases, the number of people increases)
Segment 1 is more steep than segment 2 (the number of people increases in segment 1 more than segment 2). This means that the number of people entering the arena in segment 1 was higher than the rate of people entering the arena in segment 2.
Answer:
19°
Step-by-step explanation:
I have attached an image showing this elevation.
From the image, let's first find the angle A by using cosine rule.
Thus;
8.1² = 5.5² + 13.1² - 2(5.5 × 13.1)cos A
65.61 = 30.25 + 171.61 - 144.1cos A
144.1cos A = 171.61 + 30.25 - 65.61
144.1cosA = 136.25
cosA = 136.25/144.1
cosA = 0.9455
A = cos^(-1) 0.9455
A = 19°
What you can do in this case is a rule of three to determine the length of each bow.
We have then:
1/4 ---> 2
x ------> 1
Clearing x we have:
x = (1/2) * (1/4)
x = 1/8
Answer:
the length of ribbon in each bow is
x = 1/8
Equivalently:
x = (1/4) / 2
Option 3