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Murljashka [212]

3 years ago

14

An art teacher needs to 5 boxes of markrrs to complete a project with a class of 20 students. How many boxes of markers will he

need to buy for a class of 28 students?

1 answer:

sleet_krkn [62]3 years ago

4 0

20students : 5 boxes

Divided by 5

4students : 1 boxes

28students : x boxes

28/4 = 7

28students : 7 boxes

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Use the cosine ratio or the inverse cosine to solve for x. Round your answer to the nearest tenth.

maria [59]

Answer:

x ≈ 12.6 m

Step-by-step explanation:

By using cosine ratio in the given right triangle RTS,

cos(S)° = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

cos(33)° = $\frac{\text{ST}}{\text{SR}}$

cos(33)° = $\frac{x}{15}$

x = 15.cos(33)°

x = 12.58

x ≈ 12.6 m

Therefore, measure of side ST = 12.6 m is the answer.

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Gap sells jeans that cost $21.00 for a selling price of $29.95. The percent of markup based on cost is

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If Gap sells jeans that cost $21.00 for selling price of $29.95. The percent of markup based on cost is approximately 43%. The markup in price is exactly $8.95.

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3 years ago

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12. The weight of 7 chocolate bars in grams are 131, 127,125,127,133,129 and 127

Amanda [17]

Answer:

The range is from 125 to 133.

Step-by-step explanation:

That's the lowest and highest the weights go, therefore the range is from 125 and anything in between up to 133.

7 0

3 years ago

Use the row of numbers shown below to generate 12 random numbers between 01 and 99.

sattari [20]

Answer:

Below is the complete step-by-step explanation.

Step-by-step explanation:

Given the row of numbers

25060 12315 86244 97348 36173 32710 80033 16160

<u>Taking 25060 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (25060) into your calculator. 25060 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

85 90 62 45 26 97 40 55 67 17 10 32

<u>Taking 12315 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (12315) into your calculator. 12315 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

33 20 26 68 73 09 46 14 82 74 17 04

<u>Taking 86244 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (86244) into your calculator. 86244 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

54 93 02 50 37 01 86 51 38 28 23 36

<u>Taking 97348 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (97348) into your calculator. 97348 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

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<u>Taking 36173 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (36173) into your calculator. 36173 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

13 03 28 17 14 31 98 47 40 48 68 19

<u>Taking 32710 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (32710) into your calculator. 32710 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

22 80 42 03 27 89 98 46 14 31 72 56

<u>Taking 80033 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
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Seed the number (80033) into your calculator. 80033 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

29 86 51 01 23 64 37 36 35 72 14 59

<u>Taking 16160 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (16160) into your calculator. 16160 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

93 54 72 58 30 14 48 87 99 95 83 29

Keywords: random number generator

Learn more about random number generator from brainly.com/question/1601128

#learnwithBrainly

6 0

3 years ago

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

3 years ago