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skelet666 [1.2K]
3 years ago
5

6y-5=11 what the answer I’m having a hard time finding it

Mathematics
2 answers:
QveST [7]3 years ago
6 0

6y-5=11

Move -5 to the other side. Sign changes from -5 to +5.

6y-5+5=11+5

6y=11+5

6y=16

Divide by 6 for both sides to get y by itself.

6y/6=16/6

Cross out 6 and 6, divide by 6 and then becomes 1*1*y=y

y=16/6

Reduce 16/6 by dividing by 2

16/2=8

6/2=3

Answer: y=8/3 or y=2 2/3

monitta3 years ago
6 0
Add 5 on each side leaving you with 6y=16. Then divide by 6 on each side leaving you with y=16/6. Reducing it gives you y=8/3
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Lan make 60 cakes. he gives 1/4 of the cakes to Helen. he gives 20 of the 60 cakes to sue. what fraction of the 60 cakes does he
weqwewe [10]

Answer:

5/12

Step-by-step explanation:

1/4 of the cakes is 60 divided by 4 which is 15. That goes to Helen

20 go to Sue

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4 0
3 years ago
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The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente
diamong [38]

The <em>matrix operation</em> is the <em>addition subtraction </em>and <em>multiplication </em>involving matrices.  The coordinates of the <em>image </em>can be represented as a matrix obtained from the coordinates of the <em>preimage </em>through matrix operations

The best correct option is<u> option D)</u>,<em> (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows</em>:

\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the <em>coordinates</em> of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The <em>coordinates </em>of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the  vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by <em>multiplying by</em> (-1)

Therefore, the required matrix operation is presented as follows:

\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]

Therefore, the <em>best correct</em> option is option D)

Learn more about matrix operations here:

brainly.com/question/17141646

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Answer:

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Step-by-step explanation:

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