Answer:
a) m arc AD = 145
b) D = 10
Step-by-step explanation:
a) mAD can be found because triangle OCM can be shown to be congruent to triangle ODM.
The angle AOD is supplementary to DOB which we just showed to be congruent to the known 35° angle COB. Therefore AOD = 180 - 35 = 145°
The arc length is identical to the arc angle when measured between radii.
b) The radius OC = √(OM² + (CD/2)² = √(3² + 4²) = 5.
Diameter is twice radius = 10
Answer:
9.6 square inches.
Step-by-step explanation:
We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.
First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:
Solve for the scale factor <em>k: </em>
<em />
<em />
<em />
Recall that to scale areas, we square the scale factor.
In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.
Hence, the area of ΔEDF is:
In conclusion, the area of ΔEDF is 9.6 square inches.
68+70=180
=138=180
=180-138
=42 degrees (using angle sum property of triangles
Hope this helps you
The corresponding segments WX and ZY in the image are parallel.
When a shape is translated from location to another, the size and shape of the figure do not change. Therefore, lines that are corresponding are still parallel.
Answer:
A
Step-by-step explanation:
6/3 = 2
