8 times 8=64,
9 times 9 = 81,
10 times 10= 100,
First, solve the given system of linear equations.
Second, multiply the first equation by 4 (which was an arbitrary choice). Add your result to the 2nd equation.
You should now have the following:
First equation: No change: <span>2x + 7y = 1
Second equation: 4(</span><span>-3x – 4y = 5) = -12x -16y = 20
Solve this new system of linear equations. Do you (or do you not) obtain the same solution as your earlier one?</span>
The answer is ten if I'm correct