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satela [25.4K]
3 years ago
11

Why does the skier's velocity increase as he races downhill?​

Physics
1 answer:
SSSSS [86.1K]3 years ago
3 0
Downhill skiing is also called alpine skiing. It involves high speed and quick turns down a sloped terrain. The skier gains speed by converting gravitational potential energy into kinetic energy of motion. So the more a skier descends down a hill, the faster he goes.
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What is the current when the resistance is 5 ohms and the voltage is 10 volts?
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Ohm's Law states V = IR
So,
I = V/R
The answer is B. 10/5=2 amps
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What is epsilon zero and why does it come into use, particularly in the case of Gauss's Law?
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Which statements best describe the atoms of the gas neon? Check all that apply.
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3 years ago
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Two objects gravitationally attract with a force of 100 N. If the mass of one object is doubled and the mass of the other object
barxatty [35]

Hello!

Recall the equation for gravitational force:
F_g = \frac{Gm_1m_2}{r^2}

Fg = Force of gravity (N)
G = Gravitational constant

m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)

There is a DIRECT relationship between mass and gravitational force.

We are given:
F_g = 100N

If we were to double one mass and triple another, according to the equation:
F'_g = \frac{G(2m_1)(3m_2)}{r^2} = 6(\frac{G(m_1)(m_2)}{r^2}) = 6F_g

Thus:
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5 0
3 years ago
An object experiences an acceleration of -6.8 m/s​2.​ As a result, it accelerates from 54 m/s to a complete stop. How much dista
inessss [21]

Answer:

The distance traveled during its acceleration, d = 214.38 m

Explanation:

Given,

The object's acceleration, a = -6.8 m/s²

The initial speed of the object, u = 54 m/s

The final speed of the object, v = 0

The acceleration of the object is given by the formula,

                                      a = (v - u) / t   m/s²

       ∴                              t = (v - u) / a

                                         = (0 - 54) / (-6.8)

                                         = 7.94 s

The average velocity of the object,

                                       V = (54 + 0)/2

                                           = 27 m/s

The displacement of the object,

                                 d = V x t   meter

                                    = 27 x 7.94

                                    = 214.38 m

Hence, the distance the object traveled during that acceleration is, a = 214.38 m

3 0
3 years ago
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