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klemol [59]
3 years ago
14

A 1.5m wire carries a 4 A current when a potential difference of 63 V is applied. What is the resistance of the wire?

Physics
1 answer:
Korvikt [17]3 years ago
6 0
Resistance = voltage / current
Resistance = 63 / 4
Resistance = 15.75 ohms
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Pump A can fill a tank of water in 5 hours. Pump B can fill the same tank in 8 hours. How long does it take the two pumps workin
valina [46]

Answer:

It will take both pumps 3.08 hours to fill the tank working together.

Explanation:

Pump A can fill the tank in 5 hours. Assuming that the pump gives out a steady flow of water, in one hour, pump A can fill 1/5th of the tank. Similarly, pump B in an hour, fills up 1/8th of the tank.

We must add up these two values, in order to find how much of the tank the two pumps can fill up together in one hour.

1/5 +1/8 =13/40

So 13/40 of the tank is filled in an hour. We need to find how many hours it will take for the entire tank to be filled. To do so, divide 40 by 13. This gives:

3.08 hours to fill up the tank.

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3 years ago
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What is the speed of light ?​
Brrunno [24]

Answer:

299792458 metres per second

Explanation:

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You observe a distant galaxy. You find that a spectral line of hydrogen that is shifted from its normal location in the visible
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Answer:

The galaxy is moving away from us

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Two balloons (m = 0.021 kg) are separated by a distance of d = 16 m. They are released from rest and observed to have an instant
evablogger [386]

(a) 2.56\cdot 10^{-5} C

According to Newton's second law, the force experienced by each balloon is given by:

F = ma

where

m = 0.021 kg is the mass

a = 1.1 m/s^2 is the acceleration

Substituting, we found:

F=(0.021)(1.1)=0.0231 N

The electrostatic force between the two balloons can be also written as

F=k\frac{Q^2}{r^2}

where

k is the Coulomb's constant

Q is the charge on each balloon

r = 16 m is their separation

Since we know the value of F, we can find Q, the magnitude of the charge on each balloon:

Q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(0.0231)(16)^2}{9\cdot 10^9}}=2.56\cdot 10^{-5} C

(b) 1.6\cdot 10^{14} electrons

The magnitude of the charge of one electron is

e=1.6\cdot 10^{-19}C

While the magnitude of the charge on one balloon is

Q=2.56\cdot 10^{-5} C

This charge can be written as

Q=Ne

where N is the number of electrons that are responsible for this charge. Solving for N, we find:

N=\frac{Q}{e}=\frac{2.56\cdot 10^{-5}}{1.6\cdot 10^{-19}}=1.6\cdot 10^{14}

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The flow of electricity in a certain path is called.
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The flow of electricity in a certain path is the circuit.

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