Answer:
8684.2 kg/m³
Explanation:
Tension in the rope as a result of the weight = 8.86 N
Tension in the rope when submerge in water = 7.84
upthrust = 8.86 - 7.84 =1.02 N = mass of water displaced × acceleration due to gravity
Mass of water displaced = 1.02 / 9.81 = 0.104 kg
density of water = mass of water / volume of water
make volume subject of the formula
volume of water displaced = mass / density ( 1000) = 0.104 / 1000 = 0.000104 m³
volume of the object = volume of water displaced
density of the object = mass of the object / volume of the object = (8.86 / 9.81) / 0.000104 = 0.9032 / 0.000104 = 8684.2 kg/m³
Answer:
1.5 A
Explanation:
Applying
V = IR'....................... Equation 1
make I the subject of the equation
I = V/R'.................. Equation 2
Where V = Voltage, I = current, R' = Total resistance.
From the question,
In a series connection,
R' = 0.2+0.3+0.5+5 = 6 ohm.
Given: V = 9V
Substitute into equation 2
I = 9/6
I = 1.5 A.
Note: Since all the resistors are connected in series, thesame current flows through them
Therefore the current flowing through the 5 ohm resistor = 1.5 A
We know that P = hρg
Where:
P - pressure Pa,
h - height in meter,
ρ – would be the density in kg / m^3; and
g - acceleration due to gravity is m / s^2
p = hρg if h = 0.735 meter, ρ = 13600 kg / meter^3, g = 10 meter/ sec^2
p = 0.735*13600*10 = 99960 Pa or
P = 1 x 10^5 Pa
Now with sea water if we have to make a barometer:
ρ = 1100 kg / meter^3 (given)
P = hρg if we put the value of P calculated and the value of ρ = 1100 kg /
meter^3 given, we will
get, 1 x 10^5 = h*1100*10
therefore, h = 9.09 meter or 29.82 feet of water.
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