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Feliz [49]
3 years ago
8

What are the coordinates of a point on the unit circle if the angle formed by the positive x-axis and the radius is 330°?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0
This is what I could find.


Draw a 53° angle in standard position together with a unit circle<span>. Use the triangle below to </span>find<span> the x- any y-</span>coordinates<span> of the </span>point<span> of intersection of the terminal side and the </span>circle<span>. Compute and . Confirm that they are equal to and .</span>
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Can someone please help me???<br><br> a is 3/4<br> b is -8<br> c is -2<br> d is 3
Pavel [41]

Answer:

-b[a + (c-d)^2]

-(-8)[3/4 + (-2 -3)^2]

8 [3/4 + (-5)^2]

8 [3/4 + 25]

8 [25.75]

206

5 0
3 years ago
Read 2 more answers
The midpoint of GH is M( 6,-4). One endpoint is G(8,-2). Find the coordinates of endpoint H.
Finger [1]

Using the midpoint formula, the coordinates of endpoint H are (4, -6).

<h3>The Midpoint Formula</h3>

The midpoint formula is given as: (x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )

<em>Where</em>,

(x_m, y_m) = coordinates of the midpoint

(x_1, y_1) = coordinates of the first point

(x_2, y_2) = coordinates of the second point

Given the following:

(x_m, y_m) = M( 6,-4)

(x_1, y_1) = G(8,-2)

(x_2, y_2) = H(?, ?)

Plug in the values into the midpoint formula

M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )

Solve for the x-coordinate and y-coordinate separately

6 = \frac{8 + x_2}{2}

  • Multiply both sides

6 \times 2 = 8 + x_2\\\\12 = 8 + x_2\\\\12 - 8 = x_2\\\\4 = x_2\\\\\mathbf{x_2 = 4}

-4 = \frac{-2 + y_2}{2}\\\\-8 = -2 + y_2\\\\-8 + 2 = y_2\\\\-6 = y_2\\\\\mathbf{y_2 = -6}

Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

brainly.com/question/13115533

3 0
2 years ago
What is the slope of this graph?<br> a. 4<br> b. -4<br> c. -1/4 <br> d. 1/4
kykrilka [37]

The answer is -4 i just did the test

6 0
3 years ago
Cora is using successive approximations to estimate a positive solution to
Advocard [28]
Um...... what......?
7 0
3 years ago
Multiply and solve for x: x(x + 12) – 8x = 14 + x(x – 4)
erik [133]
Using the distribution method:

x^2 + 12x - 8x = 14 + x^2 - 4x

x^2 + 4x = x^2 - 4x + 14

Now, I'm isolating x by moving all the x's onto one side of the equation:

x^2 - x^2 + 4x + 4x = 14

Combine like terms (x^2 cancels out):

8x = 14

x = 14/8

Simplified: x = 7/4
6 0
3 years ago
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