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4 years ago

6

"If we increase the frequency of transverse waves on a string, what happens to the period of oscillation of any given point on t

he string?"

1 answer:

Vlad1618 [11]4 years ago

5 0

Answer:

Period will decrease

Explanation:

Because from the relationship

T = K/f

Period inversely proportional to frequency so as frequency increase period decrease and vice versa

You might be interested in

What is the frequency if 140 waves pass in 2 minutes?

Paha777 [63]

Answer:

1.16 Hz

Explanation:

frequency, basically, is the number of wave on 1 second

so, in math we write like this

f = n/t

n = number of waves

t = time to do that (in sec)

f = 140/120 = 7/6 Hz

f = 1.16 Hz

8 0

3 years ago

You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball

const2013 [10]

Answer:

The building is 61.19 m tall, approximately.

Explanation:

From the parabollic movement trayectory equation,

$y=H+\frac{v_{0y}}{v_x}x-\frac{1}{2v_x^2}gx^2,$

where H is the initial height of the ball and $v_{oy}$ and $v_x$ the inital velocities in the vertical and horizontal direction, respectively; we have

$H=y-\frac{v_{0y}}{v_x}x+\frac{1}{2v_x^2}gx^2$ .

In this case, the ball landed at the coordinates $\left(x,y\right)=\left(61,0\right)$ , so

$H=0-\frac{17\sin\left(43\deg\right)}{17\cos\left(43\deg\right)}\times 61+\frac{1}{2\left(17\cos\left(43\deg\right)\right)^2}\times 9.81\times 61^2 \approx 61.19$ .

8 0

3 years ago

Three solid, uniform, cylindrical flywheels, each of mass 65.0 kg and radius 1.47 m, rotate independently around a common axis t

Mkey [24]

Answer:

the angular momentum is 1015.52 kg m²/s

Explanation:

given data

mass of each flywheel, m = 65 kg

radius of flywheel, r = 1.47 m

ω1 = 8.94 rad/s

ω2 = - 3.42 rad/s

to find out

magnitude of the net angular momentum

solution

we get here Moment of inertia that is express as

I = 0.5 m r² .................1

put here value and we get

I = 0.5 × 65 × 1.47 × 1.47

I = 70.23 kg m²

and

now we get here Angular momentum that is express as

L = I × ω ...........................2

and Net angular momentum will be

L = 2 × I x ω1 - I × ω2

put here value and we get

L = 2 × 70.23 × 8.94 - 70.23 × 3.42

L = 1015.52 kg m²/s

so

the angular momentum is 1015.52 kg m²/s

3 0

4 years ago

Which of the following is an example of changing momentum?!

ExtremeBDS [4]

Answer:

B!!!

Explanation:

5 0

3 years ago

Read 2 more answers

The maximum torque on a set of 20 square loops with edge lengths of 6 cm in a 4.0 T magnetic field is:A) 0.288 N-m.B) 4.8 N-m.C)

Vesnalui [34]

Answer:

option (D

Explanation:

Torque is given by

torque = N x i x A x B x sinФ

where, N is number of turns, A is area, b is the magnetic field and Ф be the angle between the area vector and the magnetic field vector, i be the current.

So, torque depends on the current.

option (D)

6 0

3 years ago