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nika2105 [10]
3 years ago
10

Question 1

Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0
Hello,
Please, see the detailed solution in the attached files.
Thanks.

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Nicole has 81/2 cups of yogurt to make smoothies. Each smoothie uses 3/4 cup of yogurt. What is the maximum number of smoothies
Virty [35]

Answer:

With that amount of yougurt she can make 54 smoothies.

Step-by-step explanation:

In order to calculate how many smoothies Nicole can make with the amount of yogurt she has we need to take the total amount of yogurt and divide it by the amount used in each smoothie. So we have:

total yorgut = 81/2 cups

each smoothie = 3/4 cup

number of smoothies = (81/2)/(3/4) = (81/2)*(4/3)

number of smoothies = 27*2 = 54 smoothies

With that amount of yougurt she can make 54 smoothies.

7 0
3 years ago
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Consider the following system of equations
Vera_Pavlovna [14]
Hsisvskevwovewhsjsbaoaa
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3 years ago
Help Please!!!!! What is the absolute value of ∣∣2 1/3 ∣∣? Use this number line to determine the absolute value. Enter your answ
SOVA2 [1]

Answer:

2\frac{1}{3}

Step-by-step explanation:

Hello!

Absolut value is just the number regardless it is negative or positive.

For example, the absolute value of -6 is 6, -82 is 82 and 5 is 5

So the absolute value of 2 1/3 is 2 1/3

Hope this helps!

4 0
4 years ago
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Tom has a water tank that holds 5 gallons of water.Tom uses water from a full tank to fill 6 bottles that each hold 16 ounces an
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1 gallon is 128 ounces, 5 gallons is 640 ounces. So 6*16=94 ounces Pitcher equals 64 ounces, so 640-158=452, there are 452 ounces of water left
4 0
3 years ago
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|x-3|&lt;2<br> |4x+1|&gt;0<br> |x-1|&lt;5<br> Ayudaaaaaaa pleaseeeee
Dafna11 [192]

Recuerda que

• |<em>x</em>| = <em>x</em> si <em>x</em> ≥ 0

• |<em>x</em>| = -<em>x</em> si <em>x</em> < 0

Necesitas considerar dos casos:

• si <em>x</em> - 3 ≥ 0,

|<em>x</em> - 3| < 1   ⇒  <em>x</em> - 3 < 1   ⇒   <em>x</em> < 4

• si <em>x</em> - 3 < 0,

|<em>x</em> - 3| < 1   ⇒   -(<em>x</em> - 3) = 3 - <em>x</em> < 1   ⇒   -<em>x</em> < -2   ⇒   <em>x</em> > 2

Entonces la solución consta de todos los números reales <em>x</em> tales que <em>x</em> > 2 y <em>x</em> < 4, o simplemente 2 < <em>x</em> < 4.

El método para resolver las otras desigualdades es el mismo.

|4<em>x</em> + 1| > 0   ⇒   4<em>x</em> + 1 > 0   o   -(4<em>x</em> + 1) > 0

…   ⇒   4<em>x</em> + 1 > 0   o   -4<em>x</em> - 1 > 0

…   ⇒   4<em>x</em> > -1   o   -4<em>x</em> > 1

…   ⇒   <em>x</em> > -1/4   o   <em>x</em> < -1/4

⇒   <em>x</em> ≠ -1/4

|<em>x</em> - 1| < 5   ⇒   <em>x</em> - 1 < 5   o   -(<em>x</em> - 1) < 5

…   ⇒   <em>x</em> - 1 < 5   o   -<em>x</em> + 1 < 5

…   ⇒   <em>x</em> < 6   o   -<em>x</em> < 4

…   ⇒   <em>x</em> < 6   o   <em>x</em> > -4

⇒   -4 < <em>x</em> < 6

7 0
3 years ago
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