Answer:
B meet A 0.01 km east of flagpole
Explanation:
given data
distance A = 5.7 km west
velocity V1 = 8.9 km/h
distance B = 4.5 km east
velocity V2 = 7 km/h
to find out
How far runners from the flagpole, when paths cross
solution
we know A and B are 5.7 + 4.5 = 10.2 km apart
and we consider here B will run distance x km for meet
so time will be for B is
time B = distance / velocity
time B = x / 7 ...................1
and
for A distance for meet = ( 10.2 - x ) km
so time A = distance / velocity
time A = ( 10.2 - x ) / 8.9 .............2
now equating equation 1 and 2
time A = time B
x / 7 = ( 10.2 - x ) / 8.9
x = 4.490
so distance of B run for meet is 4.490 km
so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km
so B meet A 0.01 km east of flagpole
Answer:
It will go about 45-50 mph.
Explanation:
Depending on what you are hauling.
Answer:
9.6J+88.2J=97.8J
Explanation:
Here the velocity of the seagull is given,mass is given and its height.
We have to find its mechanical energy my friend.
Mechanical energy=kinetic energy + potential energy.
First we will find kinetic energy.
For calculating kinetic energy we need mass and velocity,which are given here.
So, Ek=

So by substituting the values we get 9.6J.
Now we find the potential energy which is mgh.
By substituting the values we get 88.2J.
Then we add both of those and get 97.8J
I hope this satisfies you and make sure you contact me if it doesn't
If its not Distance traveled then its energy