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stepan [7]
3 years ago
14

A spring-mass system has a spring constant of 3 N/m. A mass of 2 kg is attached to the spring, and the motion takes place in a v

iscous fluid that offers a resistance numerically equal to the magnitude of the instantaneous velocity. If the system is driven by an external force of (21 cos 3t − 14 sin 3t) N, determine the steady state response. Express your answer in the form R cos(ωt − δ). (Let u(t) be the displacement of the mass from its equilibrium position at time t.)

Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

Ut = –(√2)/6 ×Cos(3t + π/4)

Explanation:

Please see the attachments below.

This problem requires some knowledge of calculus to solve as it deals with differential equations.

The solution has been explained in detail, step by step.

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<h2>The answer will be:</h2>

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What is difference between non uniform and uniform circular motion?
statuscvo [17]

Answer:

The object in a uniform motion covers same distances in an equal time period. Objects in a non-uniform motion cover dissimilar distances in an equal time period.

Explanation:

The speed of the object traveling in uniform motion is constant, the actual speed and the average speed of the moving body is same.

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A NASA satellite has just observed an asteroid that is on a collision course with the Earth. The asteroid has an estimated mass,
Citrus2011 [14]

Answer:

v = 7934.2 m/s

Explanation:

Here the total energy of the Asteroid and the Earth system will remains conserved

So we will have

-\frac{GMm}{r} + \frac{1}{2}mv_0^2 = -\frac{GMm}{R} + \frac{1}{2}mv^2

now we know that

v_0 = 660 m/s

M = 5.98 \times 10^{24} kg

m = 5 \times 10^9 kg

r = 4 \times 10^9 m

R = 6.37 \times 10^6 m

now from above formula

GMm(\frac{1}{R} - \frac{1}{r}) + \frac{1}{2}mv_0^2 = \frac{1}{2}mv^2

now we have

2GM(\frac{1}{R} - \frac{1}{r}) + v_0^2 = v^2

now plug in all data

2(6.67 \times 10^{-11})(5.98 \times 10^{24})(\frac{1}{6.37 \times 10^6} - \frac{1}{4 \times 10^9}) + (660)^2 = v^2

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5 0
3 years ago
Predict using Boyle's law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.
kobusy [5.1K]

The volume of the balloon will halve

Explanation:

Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

pV=const.

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

p_1 V_1 = p_2 V_2

And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:

p_1 = 101 kPa is the initial pressure at sea level (the atmospheric pressure)

V_1 is the initial volume

p_2 = 202 kPa is the final pressure

V_2 is the final volume

Substituting into the equation, we find:

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Which means that the volume of the balloon will halve.

Learn more about ideal gases:

brainly.com/question/9321544

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#LearnwithBrainly

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