I found the common multiple which was 12 so I multiplied 12 to all the fractions which gave an improper fraction that turned into a whole number. I hope this helps if you have any questions just ask me and I will answer.
Answer:
Using the concept of speed-distance-time, we find that the diameter of the circular path is 12 inches.
Step-by-step explanation:
Given that the object completes one revolution in 8 seconds. So, the circular speed of the object is 2πr/8 = πr/4 inches per seconds, where r is the radius of the circular path. The speed can be written as:
πr/4 inches per seconds = 60πr/4 inches per minute = 15πr inches per minute.
But, it is given that the circular speed of the object is 90π inches per minute. So,
90π = 15πr
r = 6 inches
Since, diameter is the double of radius, d = 2r = 12 inches.
For more explanation, refer the following link:
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The answer is 2, 12 meters
Answer:36.80
Step-by-step explanation:
15% of 32 is 4.8 so add that
Answer:
2.225
Step-by-step explanation:
To find how long the object will be in the air, we just need to find the time when the object reaches the ground, that is, f(t) = 0
So, we have that:
0 = −16t2+32t+8
2t2-4t-1 = 0
Using Bhaskara's formula:
Delta = b2 - 4ac = 16 + 8 = 24
sqrt(Delta) = 4.899
t = (-b + sqrt(Delta)) / 2a
t = (4 + 4.899) / 4
t = 2.2248
Rounding to nearest hundredth, we have t = 2.225
