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SCORPION-xisa [38]
3 years ago
15

Simplify the expression: 7(5 − 3h)

Mathematics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{45 - 21h}}}}}

Step-by-step explanation:

\sf{7(5 - 3h)}

Distribute 7 through the parentheses

\dashrightarrow{ \sf{7 \times 5 - 7 \times 3h}}

\dashrightarrow{ \sf{45 - 21h}}

Hope I helped!

Best regards! :D

suter [353]3 years ago
6 0

Answer:

14h

Step-by-step explanation:

7(5-3h)

you do distributive property on the first step.

35-21h

then you subtract the two.

14h is your answer.

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Mia has 12 marbles, alex has 9 marbles, and micheal has 51 marbles. use the gcf and the distributive property to find the total
aleksley [76]

Answer: 5508

Step-by-step explanation:

all the numbers together equal 72 marbles in total.

(6x2)x (3x3)x (3x17)=

  12       9          51              first multiply the easy numbers 12x9 =108 then

108x51= 5508

3 0
3 years ago
If the door to the library is at (2, 4), the door to the mall is at (8, 2), and one
guapka [62]

Answer:

6 miles

Step-by-step explanation:

The distance formula is expressed as;

D = √(x2-x1)²+(y2-y1)²

D = √(2-4)²+(8-2)²

D = √(-2)²+(6)²

D = √4 + 36

AD = √40

AD = 6.32

Hence the approximate distance between the library  and the mall is 6 miles

5 0
3 years ago
Find csc 0, sin 0, and cot 0, where is the angle shown in the figure. Give exact values, not decimals approximations. (LISTING B
dexar [7]

Answer:

sup

Step-by-step explanation:

sup

4 0
3 years ago
A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).
JulsSmile [24]
The answer is 16.8 units
7 0
3 years ago
Read 2 more answers
[ Easy Math ] Help me pls
goldfiish [28.3K]

Answer:

1) you're going to have to flip the coins (or fake numbers) for the experimental trials.

2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.

When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.

|(100-50)| ÷ 50 = 50÷50 = 1.00

So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.

Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:

|(4-5)| ÷ 5 = 1÷5 = 0.20

So increasing the # flips DECREASES the deviation value!!

Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip

7 0
3 years ago
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