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Firdavs [7]
3 years ago
11

Which number belongs to the set of integers but does NOT belong to the set of natural numbers? * 10 points Captionless Image A B

C D
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

awnser: -5

hope this helps

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87 degrees is the answer
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Read 2 more answers
Find the area of the following figure with the indicated dimensions.use pi.
slega [8]
It's a half circle plus a triangle.
The diameter of the circle is 23.1 ft so the radius is 11.55

Area of a circle is πr²
Area of a triangle is (1/2)bh

Area shape = (1/2)πr² (1/2)bh
A = (1/2)π(11.55)² + (1/2)(23.1)(29.4)
A = 549.1181
4 0
4 years ago
Finding the missing angles ?
bazaltina [42]

Answer:

1. 46

2. 46

3. 134

4. 134

5. 46

6. 46

7. 134

This is going from top right, left to right.

8 0
2 years ago
What is the area of a bedroom thats 12 ft in length and 10 ft in width?
ludmilkaskok [199]

Answer:

120 sq ft.

Step-by-step explanation:

REMEMBER: Area is found by multiplying one side, by the other side that isn't the same length as it.

Multiply 12 by 10 to get 120

120 is the area of the bedroom

3 0
3 years ago
According to one investigator’s model, the data are like 400 draws made at random from a large box. The null hypothesis says tha
tankabanditka [31]

Answer:

z=\frac{52.75-50}{\frac{25}{\sqrt{400}}}=2.2    

p_v =2*P(Z>2.2)=0.0278  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the mean is significantly diffrent fro 50 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=52.75 represent the mean height for the sample  

s=25 represent the sample standard deviation

n=400 sample size  

\mu_o =50 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 50 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 50  

Alternative hypothesis:\mu \neq 50  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value but we can assume it as z distribution, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{52.75-50}{\frac{25}{\sqrt{400}}}=2.2    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(Z>2.2)=0.0278  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the mean is significantly diffrent fro 50 at 1% of signficance.  

3 0
4 years ago
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