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larisa [96]
4 years ago
12

Find the area of the trapezoid.

Mathematics
1 answer:
mrs_skeptik [129]4 years ago
6 0

Answer:

40cm^2

Step-by-step explanation:

A=a+b/2×h

A=6+10/2*5

A=16cm/2*5cm

A=8cm*5cm

A=40cm^2

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1.5.5 Practice: Modeling: Best Ticket Deal
posledela

The best ticket deal are illustrations of linear equations

The ticket system is a better deal to the max ticket

<h3>How to determine the best ticket deal</h3>

From the complete question, we have the following summary:

  • <u>Ticket System</u>

Charges = $22 per person

Surcharge = $10 per transaction

  • <u>Max Tickets</u>

Charges = $20 per person

Surcharge = $16 per transaction

Assume there would be only one transaction, the linear equations that represent the ticket deals are:

Ticket System: y = 22x + 10

Max Ticket: y = 20x + 16

The costs of ticket for two people in both deals are:

Ticket System: y = 22*2 + 10 = 54

Max Ticket: y = 20*2 + 16 = 56

By comparison;

54 is less than 56

This means that the ticket system is a better deal to the max ticket

Read more about linear equations at:

brainly.com/question/14323743

4 0
2 years ago
Write 580408360009 in wards
UNO [17]
Five hundred eight billion, four hundred eight million, three hundred sixty thousand, nine.
4 0
3 years ago
Read 2 more answers
Help please help by showing work i couldn't understand and when answering both questions please say which question you are answe
Digiron [165]
16) y varies directly as x is the same thing as y=mx where m is the constant
for the first equation where the length is 7 and weight is 49 there fore
7=m49 in which m=1/7 so to find the length of the 2nd equation
y=m63
y=1/7 x63
y=9 inches


17)The raiser with the $6.25 would raise more money because if 25 ticket is sold and money received is $125 then each ticket is sold for $5  which means if the ticket is sold for $6.25 then 25 would bring in $156.25
4 0
3 years ago
[39 POINTS] <br> If <img src="https://tex.z-dn.net/?f=%20x%5E5k%3Da%5C%5C%20x%5E2k%5E2%3Db%20" id="TexFormula1" title=" x^5k=a\\
rjkz [21]

Given

x^5*k=a .................(1)

x^2*k=b .................(2)

We need to find x^3.

Solution:

On inspection, we note that (1)/(2) gives x^3 on the left hand side, but the division is valid on conditions that x &ne; 0 and k &ne; 0.

So we conclude:

(1) / (2)

\frac{x^5*k}{x^2*k^2} = \frac{a}{b}

=>

\frac{x^3}{k} = \frac{a}{b}

=>

x^3= \frac{ak}{b} on condition that x\ne{0} and k\ne{0}



7 0
3 years ago
Read 2 more answers
Make a function table for y=-3x+3
Marina CMI [18]
X | Y
-2 | 9
-1 | 6
0 | 3
1 | 0
2 | -3
8 0
3 years ago
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