All that you are doing is trying to fiigure out the Frequency of all the tally marks!!
Break it down into 2-Dimensional shapes. Then add the areas together.
From the picture you can see;
front & back rectangles are 2*(4 x 8) = 64 m²
2 side rectangles are 2*(4 x 12) = 56 m²
2 triangular front & back pieces are (1/2)*8*3 = 12 m²
2 roof rectangles are 2*(5 x 12) = 120 m²
total Surface area = 64 m² + 56 m² + 12 m² + 120 m²
= 252 m²
For the volume; break it up into 3-dimenssional shapes and add the volumes together.
From the picture you can see;
Rectangular box volume is 4 x 8 x 12 = 384 m³
Triangular roof volume is area of front triangle multiplied through the length. (1/2)*8*3* 12 = 144 m³
Total volume = 384 m³ + 144 m³
= 528 m³
2. I think the answer is 24
subracting the last 2 inequalities we get
6x + 7y <= 42
3x + 2y <= 18 subtract:_-
3x + 5y <= 24
Answer:
Step-by-step explanation:
Jada is making circular invitations
we have d=12 cm, the radius r=6
she needs to find out the circumference
C=2x3.14x r
C=2x 3.14x6=37.68
180/37.68=4.77
she can make just 4 invitations
9514 1404 393
Answer:
90 m²
Step-by-step explanation:
The given linear dimensions have the ratio ...
red/blue = (6 m)/(4 m) = 3/2
The ratio of areas is the square of the ratio of the linear dimensions:
(red area)/(blue area) = (3/2)²
S = (blue area)(9/4) = (40 m²)(9/4)
S = 90 m²
