Step-by-step explanation:
Given that,
a)
X ~ Bernoulli
and Y ~ Bernoulli 
X + Y = Z
The possible value for Z are Z = 0 when X = 0 and Y = 0
and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0
If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,
Therefore Z is a Bernoulli random variable
b)
If X and Y can not be both equal to 1
then,
or 
and 

c)
If both X = 1 and Y = 1 then Z = 2
The possible values of the random variable Z are 0, 1 and 2.
since a Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution
Answer:
5 and 6
Step-by-step explanation:
-5 x 6 = -30
-5 + (6) = 1
x2 + 1x - 30 = 0
(X - 5 ) (X + 6)
To summarize, since -5 and 6 multiply to -30 and add up 1, you know that the following is true:
x2 + 1x - 30 = (X - 5 ) (X + 6)
3•2•7=42•2=84
12•10•7=840
84+840=924in^3
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