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3 years ago

1) Solve 12.5 +8= 27. What does s=

Mathematics

2 answers:

garik1379 [7]3 years ago

3 0

Answer:

there is no s in the question please explain

Step-by-step explanation:

Murljashka [212]3 years ago

3 0

Answer:

S = 6.5

Step-by-step explanation:

12.5 + 8 = 20.5,

27 - 20.5 = 6.5

therefore s = 6.5

Checking work

12.5 + 8 + s =

12.5 + 8 + 6.5 = 27

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1879 meters to kilometers

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It would be 1.879 kilometers

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3 years ago

The cargo box of an 18-wheeler truck has an inside length of 39.6 feet,width of 7.6 feet,and a height of 8.8 feet.What is the ca

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3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

3 years ago

Mark and peter went to an arcade where the machines took tokens. Marilk played 9 games of ping pong and 5 games of pinball, usin

Readme [11.4K]

Answer:

9x + 5y = 29 ........... (1) and

3x + y = 7 ........... (2)

Each game of ping pong requires 1 number of token and each game of pinball requires 4 number of tokens.

Step-by-step explanation:

Let, each game of ping pong requires x number of tokens and each game of pinball requires y number of tokens.

So, from the given conditions we can write

9x + 5y = 29 ........... (1) and

3x + y = 7 ........... (2)

Now, solving equations (1) and (2) we get,

9x + 5(7 - 3x) = 29

⇒ 35 - 6x = 29

⇒ 6x = 6

⇒ x = 1 token.

Now, putting x = 1 in equation (2) we get,

3 + y = 7

⇒ y = 4 tokens.

So, each game of ping pong requires 1 number of token and each game of pinball requires 4 number of tokens. (Answer)

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3 years ago

A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.

marta [7]

The answer is A
there is not enough hours to build everything and A has the right equation

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3 years ago

Read 2 more answers