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2 years ago

Question IS in PICTURE!!!!

Mathematics

2 answers:

julia-pushkina [17]2 years ago

8 0

IQR= Q3-Q1

Airport 1
Q3 is 8
Q1 is 2

8-2= 6

Airport 1 IQR is 6

Airport 2
Q3 is 8
Q1 is 3

8-3= 5

Airport 2 IQR Is 5

Stolb23 [73]2 years ago

7 0

Answer:

Im pretty sure its 5

Step-by-step explanation:

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What is alergbra about and why ?

Pie

Answer:

Simply put, algebra is about finding the unknown or putting real life variables into equations and then solving them. ... Algebra can include real numbers, complex numbers, matrices, vectors, and many more forms of mathematic representation

Step-by-step explanation:

4 0

2 years ago

Need help on this one question please

Elan Coil [88]

P(x, y) Q(x,y)
P(-2, -1) start at 0. Go to the left two squares, then go down 1 square. mark a point there
Q(2, 4) start at 0. Go to the right two squares, go up 4 squares. mark a point there.
connect two points
make a right triangle
Then use the pythereom
$4^{2} + 5^{2} = (PQ)^{2}$
$41 = (PQ)^{2}$
$\sqrt{41} = PQ$

6 0

2 years ago

The product of two consecutive positive integers is 29 more than their sum. Find the integers

Rina8888 [55]

The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.

Answer: the numbers would be 6 and 7.

7 0

2 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

A customer purchases 10 m dade co. florida 7.50% g.o. bonds at a 9.50 basis. how much interest will she collect each year? $75 $

crimeas [40]

In the value of bonds, the symbol "M" means "thousands.
Therefore, 10 M = 10,000$

So, the customer bought a coupon with 10,000$ and the expected annual interest is 7.5% of the coupon's value.

Calculating the value of interest is simple, just multiply the interest rate (7.5%) by the original value of the coupon to know how much interest she will collect each year.

Interest collected each year = (7.5 / 100) x 1000 = 750$

5 0

2 years ago