The answer to the problem is:
<span>8j^3 + 5j^2 - 3 - 5j^3 - 7j^2 + 12j - 7
</span>
<span>3j^3 - 2j^2 + 12j - 10
</span>
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Answer:
28.4in³
Step-by-step explanation:
Volume of the square based pyramid = L²H/3 where;
L is the length of a side of the square base
H is the height of the prism
Given
Perimeter of the base = 13.4 in
Height of the pyramid = 7.6in
First we need to get the length of the square base
Perimeter of a square = 4L
13.4 = 4L
L = 13.4/4
L = 3.35 in
Next is to find the required volume of the pyramid
V = L²H/3
V = 3.35²(7.6)/3
V = 85.291/3
V = 28.4 in³
Hence the volume of the pyramid to nearest tenth is 28.4in³
A; the probability of the number of free throws made out of 8 is at most 3.
I might be wrong, but I’m 90% sure I’m right ☺️
Draw y = -1/2x + 4 on the graph because it’s already converted into y = mx + b form. And then for the other one you get y = 1/4x + 1 and you have to graph that too! Remember rise over run too, but idk if your teacher taught you that.