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snow_lady [41]
4 years ago
5

Given that you added about 5ug of purified acid phosphatase to tube A, calculate the amount of acid phosphatase that was present

in 400uL of the wheat germ extract in the tube B.
Chemistry
1 answer:
Reil [10]4 years ago
6 0

Hey there!:

Amount of purified acid phosphatase added to tube A = 5 ug ( micrograms )

Amount of acid phosphatase present in 400 ug of wheat germ extract  in tube B :

1 / 100 = 5x / 400 =

100 x = ( 0.5 ) ( 400 ) =

x = (0.5 ) ( 400 ) = 100

x = 200 / 100

x =  2 ug


The amount of acid phosphatase present in 400 ug of the  wheat germ in tube B is 2 ug


Hope that helps!

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How many grams of hydrogen chloride can be produced from 1.00g of hydrogen and 55.0g of chlorine? what is the limiting reactant?
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Answer:

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Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required grams of HCl by firstly identifying the limiting reactant via the moles of each reactant as they are in a 1:1 mole ratio:

n_{H_2}=1.00gH_2*\frac{1molH_2}{2.02gH_2}=0.500molH_2\\\\ n_{Cl_2}=55.0gCl_2*\frac{1molCl_2}{70.9gCl_2}=0.776molCl_2

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