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snow_lady [41]
4 years ago
5

Given that you added about 5ug of purified acid phosphatase to tube A, calculate the amount of acid phosphatase that was present

in 400uL of the wheat germ extract in the tube B.
Chemistry
1 answer:
Reil [10]4 years ago
6 0

Hey there!:

Amount of purified acid phosphatase added to tube A = 5 ug ( micrograms )

Amount of acid phosphatase present in 400 ug of wheat germ extract  in tube B :

1 / 100 = 5x / 400 =

100 x = ( 0.5 ) ( 400 ) =

x = (0.5 ) ( 400 ) = 100

x = 200 / 100

x =  2 ug


The amount of acid phosphatase present in 400 ug of the  wheat germ in tube B is 2 ug


Hope that helps!

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When producing a soluble salt in a reaction between an acid and an alkali, how can you prepare dry solid crystals from the solut
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7 0
4 years ago
sodium chloride is made up of sodium and chlorine, but it isn't a poisonous gas and it doesn't explode in water. explain why.
jenyasd209 [6]

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7 0
3 years ago
At 524 mm Hg and 35 °C, a sample of gas occupies a volume of 275 ml. The gas is transferred to a 325-ml flask and the temperatur
Deffense [45]

Answer:

400.197mmHg

Explanation:

P1V1 / T1 = P2V2 / T2

Where P1=524 mm Hg V1 =275 ml T1 = 35°C +273 = 308k

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Substituting the values into the formula.

524 mm Hg ×275 ml /308k = P2×325-ml/278k

Cross multiply

524 mm Hg ×275 ml×278k=308k×P2×325-ml

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P2 = 40059800/100100

P2= 400.197mmHg

Hence, the second pressure will be 400.197mmHg

6 0
3 years ago
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