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Flauer [41]
2 years ago
14

HELP PLZ ITS DUE IN 10 MIN "Jack's model includes one object consisting of two molecules and one object consisting of six molecu

les. He put 16 energy cubes in each object and stated that his model showed the two objects at equilibrium. Explain what is wrong with Jack's model."
(I know it looks long but basically I just need help with finding what's wrong with the model)
​

Chemistry
2 answers:
soldier1979 [14.2K]2 years ago
7 0

tere gand Mein kam Dal Do

Savatey [412]2 years ago
5 0

Answer: the molecules have different energy and the system is not in equilibrium

Explanation:

The model developed by Jack has the same energy for each of the two objects, but as each object is made up of a different number of molecules, in the system with more molecules, object 2, each one has approximately 2.4 less energy and the molecules of Object 1 have an E / 2 energy.

So when you book them together the molecules have different energy and the system is not in equilibrium

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5. Forces (or actions) always come in pairs. They<br> are____and_____
azamat

Answer:

equal and opposite

Explanation:

The size of the forces on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object

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Which organism is in Kingdom Protista?<br><br> A. bacteria<br> B. virus<br> C. fungi <br> D. seaweed
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2 years ago
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What is the balanced equation for CaCO3(s) &gt; CaO(s) + CO2(g
vlada-n [284]
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1 CaCO3(s) = 1 CaO(s) + 1 CO2(g)

hope this helps!

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3 years ago
How does density determine whether an object will float?
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If the object is denser then the substance it's in, it will sink. If the object is less dense than the substance, it will float.
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). In a titration, a student obtained an average titre value of 3.9 cm3 of 0.3 M HCl. If the volume of Na2CO3 solution used is 1
Oliga [24]

Answer:

I) 0.0585 M

ii)6.2 g dm-3

Explanation:

The reaction equation is given as;

Na2CO3(aq) +2HCl(aq)------> 2NaCl(aq) + CO2(g) +H2O(l)

Concentration of acid CA= 0.3 M

Volume of acid VA= 3.9 cm^3

Concentration of base CB= the unknown

Volume of base VB= 10 cm^3

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB=CBVBNA

CB= CAVANB/VBNA

substituting values;

CB= 0.3 × 3.9 × 1/ 10.0 × 2

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5 0
3 years ago
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