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Tanya [424]
3 years ago
11

The process of fermentation involves chemical reactions that convert solid glucose (C6H12O6) into aqueous ethanol and carbon dio

xide gas. Write the balanced chemical equation
Chemistry
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

C6H12O6 —> 2C2H5OH + 2CO2

Explanation:

The equation for the reaction is given below:

C6H12O6 —> C2H5OH + CO2

We can balance the equation above as follow:

There are 12 atoms of H on the left side and 6 atoms of the right side. It can be balance by putting 2 in front of C2H5OH as shown below:

C6H12O6 —> 2C2H5OH + CO2

There are 6 atoms of C on the left side and 5 atoms on the right side. It can be balance by putting 2 in front of CO2 as shown below:

C6H12O6 —> 2C2H5OH + 2CO2

Now the equation is balanced.

You might be interested in
A thermite reaction realeses large amounts of heat and light resulting in the melting of the iron metal
lara [203]

Answer:

1. Fe₂O₃ : Al = 1 : 2

2. Fe₂O₃ : Al₂O₃ = 1 : 1

3. Fe₂O₃ : Fe = 1 : 2

Note: The question is incomplete. The complete question is given below :

A thermite reaction releases large amounts of heat and light, resulting in the melting of the iron metal that forms during the reaction. The balanced chemical equation is given below: Fe₂O₃(s) + 2Al(s) ---> Al₂O₃(s) + 2Fe(l) Determine the correct mole ratios for the following substances, based on this chemical equation.

Explanation:

A thermite reaction is a highly exothermic reaction that occurs between a mixture of powdered aluminium and iron (iii) oxide.

The reaction is a redox reaction which produces aluminium oxide and metallic iron.

The heat given out in the reaction melts the iron formed. It is used to join railway tracks or cracked machine parts. The molten iron runs down between the tracks and welds them together.

The balanced equation of the reaction is given below :

Fe₂O₃(s) + 2Al(s) ---> Al₂O₃(s) + 2Fe(l) + Heat

The mole ratio of the reactant and products are as follows:

1. 1 mole of Iron (iii) oxide and 2 moles of aluminium are combined

Fe₂O₃ : Al = 1 : 2

2. 1 mole of aluminium oxide is produced from 1 mole of iron (iii) oxide

Fe₂O₃ : Al₂O₃ = 1 : 1

3. 2 moles of of iron are produced from 1 mole of iron (iii) oxide

Fe₂O₃ : Fe = 1 : 2

4 0
3 years ago
Go'=30.5 kJ/mol
makvit [3.9K]

Answer:

a) Keq = 4.5x10^-6

b) [oxaloacetate] = 9x10^-9 M

c) 23 oxaloacetate molecules

Explanation:

a) In the standard state we have to:

ΔGo = -R*T*ln(Keq) (eq.1)

ΔGo = 30.5 kJ/moles = 30500 J/moles

R = 8.314 J*K^-1*moles^-1

Clearing Keq:

Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6

b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])

4.5x10^-6 = ([oxaloacetate]/(0.20*10)

Clearing [oxaloacetate]:

[oxaloacetate] = 9x10^-9 M

c) the radius of the mitochondria is equal to:

r = 10^-5 dm

The volume of the mitochondria is:

V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L

1 L of mitochondria contains 9x10^-9 M of oxaloacetate

Thus, 4.18x10^-42 L of mitochondria contains:

molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules

3 0
4 years ago
Which of the following is a correct variation of the Joule's law equation? O A. P= I x R2 OB. P = V + OC. P = 12 V OD. P = V2 R​
Minchanka [31]

Answer:

P=\dfrac{V^2}{R}

Explanation:

Power is defined as the rate at which energy is dissipated.

Its mathematical form is given by :

P = VI

Where

V is voltage and I is current

Using Ohm's law :

I=\dfrac{V}{R}, R is resistance

Joule's law equation is given by :

P=\dfrac{V^2}{R}

Hence, the correct option is (d).

6 0
3 years ago
The duration (length of time) of a lunar eclipse is
vlada-n [284]

Answer:

It is longer than a solar eclipse

7 0
3 years ago
Read 2 more answers
Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.
sashaice [31]

Answer:

0.00500M of Na₂C₂O₄

Explanation:

<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>

<em />

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

<h3>0.00500M of Na₂C₂O₄</h3>
4 0
3 years ago
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