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Musya8 [376]
3 years ago
12

Pls help me I’m confused of what candy this is

Chemistry
1 answer:
Leokris [45]3 years ago
8 0

Answer:

kit kat, toblerone, dairy milk

Explanation:

ganda quoh, period.

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Answer the following questions ( image) with the given options.​
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3.Ca(HCO3)2

4. use of Ca(OH)2

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3 years ago
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I need help if anyone will help plz
maksim [4K]

Answer:

D

Explanation:

If you look at the problem, and the coefficients (the little numbers on the bottom) you will see that on the reactant side you get a total of 11, you look over to the product side and you also get a total of 11.

B. is wrong because they’re are the same amounts

C.is wrong because they have the same amount of carbon

D. Now similar to B but slightly different the matter is the reactant side I’m pretty sure is equal to the amount on the product side.

If I had to take a strong guess though I would choose D just because the question is asking for the one that shows The law of conservation of mass. Pls make me brainlist

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3 years ago
The dimensions of a rectangular solid are measured to be 1.27 cm, 1.3 cm, and 2.5 cm. The volume should be recorded as
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3 years ago
What type of reaction is nitrogen bromide?
Marat540 [252]

Nitrogen tribromide is a chemical compound with the formula NBr3. It is extremely ... NBr3 was first prepared by reaction of bistrimethlysilylbromamine (bis(trimethylsilyl) amine bromide) ..

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3 years ago
You have 15 grams of ice at 0°C. How much energy is needed to melt the ice and warm it to 25°C. Ice melts at 0°C. The specific h
azamat

Answer:

d. 1600 calories

Explanation:

The heat of fusion of water, L, is the amount of heat per gram required to melt the ice to water, a process which takes place at a constant temperature of 0 °C. The specific heat of water, c, is the amount of heat required to change the temperature of 1 gram of water by 1 degree Celsius.

We will convert the units of c from Jg⁻¹°C⁻¹ to cal·g⁻¹°C⁻¹ since the answers are provided in calories. The conversion factor is 4.18 J/cal.

(4.18 Jg⁻¹°C⁻¹)(cal/4.18J) = 1 cal·g⁻¹°C⁻¹

First we calculate the heat required to melt the ice, where M is the mass:

Q = ML = (15 g)(80 cal/g) = 1200 cal

Then, we calculate the heat required to raise the temperature of water from 0 °C to 25 °C.

Q = mcΔt = (15 g)(1 cal·g⁻¹°C⁻¹)(25 °C - 0 °C) = 380 cal

The answer is rounded so that there are two significant figures

The total heat required for this process is (1200 cal + 380 cal) = 1580 cal

The rounded answer is 1600 calories.

3 0
3 years ago
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