Take the dot product, if the dot product is zero, they are orthogonal
<span>the dot product here is 15(-5) + 45(12) so the vectors are not orthogonal </span>
<span>to see if they are parallel, take the dot product again, using the definition </span>
<span>u dot v = mag u x mag v cos (theta) where mag is the magnitude of the vector and theta is the angle between them </span>
<span>we know from above that u dot v = 465 </span>
<span>mag u = sqrt[15^2+45^2]=47.43 </span>
<span>mag v = sqrt[5^2+12^2]=13 </span>
<span>so we know: </span>
<span>cos(theta) = 465/(47.43x13) = 0.75 </span>
<span>
so theta = 41 deg</span>
She would need 107.5 square cm to cover the smaller wedge of cheese.
Answer:
63+22i
Step-by-step explanation:
(8 - 3i)(6 + 5i)
FOIL
first: 8*6 = 48
outer: 8*5i = 40i
inner: -3i* 6 = -18i
last: -3i*5i = -15 i^2 = -15(-1) = 15
Add together
48+40i -18i +15
Combine like terms
63+22i
Answer:
54.1° (1 dp)
Step-by-step explanation:
Let the center point of the rectangle PQRS = M
Calculate the length of the line SM using Pythagoras' Theorem:
a² + b² = c²
(11/2)² + (7/2)² = SM²
42.5 = SM²
SM = √42.5 cm
The height of the pyramid is 9 cm, therefore, MT = 9
Now we have a right angled triangle with base SM and height MT and hypotenuse ST
We want to find the angle TSM, so we can use the trig formula tan x = O/A, where x is the angle, O is MT and A is SM
tan TSM = MT/SM = 9/√42.5
TSM = arctan (9/√42.5) = 54.082088°
So the angle between the line ST and the plane PQRS = 54.1° (1 dp)
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