One gram is larger then one ounce one gram = 0.03 ounces
Answer:
10. ⅔ − ∛e
11. 79 + 3√3
Step-by-step explanation:
10. ∫ (1 + 1/x) dx
∫ dx + ∫ (1/x) dx
These are both standard integrals.
x + ln|x| + C
Evaluate between x = ∛e and x = 1.
(1 + ln|1| + C) − (∛e + ln|∛e| + C)
1 + 0 + C − ∛e − ⅓ − C
⅔ − ∛e
11. ∫₁³ (4x³ + ³/₂√x) dx
∫₁³ 4x³ dx + ∫₁³ (³/₂ x^½) dx
(x⁴ + x^(³/₂) + C) |₁³
(x⁴ + x√x + C) |₁³
(3⁴ + 3√3 + C) − (1⁴ + 1√1 + C)
81 + 3√3 + C − 1 − 1 − C
79 + 3√3
You would estimate 3.4 down to 3 and 5.6 up to 6. So you would do 3 times 6=18
Answer:
The intensity becomes one fourth when the distance is doubled.
Step-by-step explanation:
The statement is
Intensity of light varies inversly as the square of the distance
So we get
Now for distance 12in let the intensity be
So we get
...(1)
For distance 24in, let the intensity be
We get
....(2)
Dividing (1) by (2) we get
Hence the intensity becomes one fourth