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vovangra [49]
4 years ago
5

Can someone help me with this 2x+4y+3z=6 x-2y+z=-5 -x-3y-2z=-7 solve for x,y,z

Mathematics
1 answer:
Flauer [41]4 years ago
3 0

Answer:

x = -7 2/3, y = 1 1/3 and z = 5 1/3.

Step-by-step explanation:

2x+4y+3z=6    .....  1

x-2y+z=-5        ...... 2

-x-3y-2z=-7      .......3

Add equations 2 and 3 to eliminate x:

-5y - z = -12   .....4

Multiply equation 2 by - 2:

-2x + 4y  - 2z = 10

Add this to equation 1:

8y + z = 16   ........ 5

Now add equation 4 to equation 5:

3y = 4

y = 4/3 = 1 1/3.

Now find z by substituting for y in equation 4:

-5(4/3) - z = -12

z = 12 - 20/3

z = 36/3 - 20/3 = 16/3 = 5 1/3.

Finally, we find x by substituting for y and z in equation 1:

2x + 4*4/3 + 3*16/3 = 6

2x = 6 - 16/3 - 16

2x =  18/3 - 16/3 - 48/3 = -46/3

x = 23/3 =  7 2/3.

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Answer:

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Step-by-step explanation:

1/5 of 1 hour = 20 minutes

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Hope this helps!

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Step-by-step explanation:

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3 years ago
Aditya determines the remainder of -12x¹⁷+3x⁵-9x²-1/x+1 using the remainder theorem. How does he proceed to the correct answer?
Alenkasestr [34]

Answer:

Aditya evaluates the numerator of the expression when x = –1. He finds the remainder of the division to be –1

Step-by-step explanation:

– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1

To obtain the answer to question, let us apply the remainder theorem. This is illustrated below:

Assume:

x + 1 = 0

Subtract 1 from both side

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Next, we shall substitute the value of x into – 12x¹⁷+ 3x⁵ – 9x² – 1. This is illustrated below:

– 12x¹⁷+ 3x⁵ – 9x² – 1

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– 12(–1)¹⁷+ 3(–1)⁵ – 9(–1)² – 1

– 12(–1) + 3(–1) – 9(1) – 1

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= –1

Thus, using the remainder theorem,

– 12x¹⁷+ 3x⁵ – 9x² – 1 / x + 1 will result to –1

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