All categories

3 years ago

PLEASE HELP ME WITH THIS PLEASEE

Mathematics

2 answers:

andreev551 [17]3 years ago

6 0

-0.20

if u need explanation just msg me

Jobisdone [24]3 years ago

5 0

Well first you want to get the denominator to ten because then it is easier to convert it to a decimal.

-1*2=-2

5*2=10

Then you know that 2/10 equals 0.2 and since theres a negative sign in front of it your answer is -0.2

Hope this helps :)

You might be interested in

What is the value of x (distance from the edge of the screen to the end of the wall) if the area of the screen is 40 m^2?

erica [24]

The value of x that is the length from the edge of the screen to the end of the wall is equal 3. This is derived from an equation which serves as a function of the Area. See the solution below.

<h3>

What is the calculation for the solution above?</h3>

Recall that the area of the entire wall is 40m².

(10-2x) (16- 2x) = 40

Expanding the brackets, we have

160-20x-32x + 4x² = 40
4x² - 52x + 120 = 0
x² - 13x +30 = 0

Using the quadratic equation

x = (-b±√b²-4ac)/2a

Where a = 1
b = 13
c = 30

x = (13 ± 7)/2

Thus x = 10; or x = 3.

x cannot be the answer because it invalidates 16-x<0;

Hence, the correct answer is x = 3

Learn more about Areas at:
#SPJ1

7 0

2 years ago

A point moves along the curve y = √ x in such a way that the y-component of the position of the point is increasing at a rate of

Eduardwww [97]

Answer:

The value of x component changes at a rate of $\frac{dx}{dt}=4\sqrt{x}$ units per second

Step-by-step explanation:

We are given that $y=x^{\frac{1}{2}}$

Differentiating on both sides with respect to time we get

$\frac{dy}{dt}=\frac{d\sqrt{x}}{dt}\\\\\frac{dy}{dt}=\frac{1}{2}x^{\frac{-1}{2}}(\frac{dx}{dt})\\\\\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}$

It is given that $\frac{dy}{dt}=2units/sec$

Solving for $\frac{dx}{dt}$ we get

$\frac{dx}{dt}=\frac{dy}{dt}\times 2\sqrt{x}\\\\\frac{dx}{dt}=4\sqrt{x}$

5 0

3 years ago

Which of the following methods would be the easiest to use to solve 12x2 – 48 = 0?

Katarina [22]

$\bf \stackrel{\textit{solving for \underline{x}}}{12x^2-48=0\implies 12x^2=48\implies x^2=\cfrac{48}{12}\implies x^2=4} \\\\\\ x=\pm\sqrt{4}\implies x=\pm 2$

7 0

3 years ago

Read 2 more answers

Lucy and Ricky buy a home. They plan to make a down payment and carry an $82,500 mortgage. Closing costs are $2,000 and are adde

Anon25 [30]

The awnser is b um I won't say anything else

8 0

3 years ago

Read 2 more answers

For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

3 0

3 years ago