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jarptica [38.1K]
2 years ago
14

PLEASE HELP ME WITH THIS PLEASEE

Mathematics
2 answers:
andreev551 [17]2 years ago
6 0
-0.20

if u need explanation just msg me
Jobisdone [24]2 years ago
5 0

Well first you want to get the denominator to ten because then it is easier to convert it to a decimal.

-1*2=-2

5*2=10

Then you know that 2/10 equals 0.2 and since theres a negative sign in front of it your answer is -0.2

Hope this helps :)

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Problem: The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72
Lisa [10]

Answer:

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

Step-by-step explanation:

To solve these questions, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.

This means that \mu = 38.72, \sigma = 3.17

Sample of 10:

This means that n = 10, s = \frac{3.17}{\sqrt{10}}

Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

This is 1 subtracted by the p-value of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}

Z = 1.28

Z = 1.28 has a p-value of 0.8997

1 - 0.8997 = 0.1003

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

\mu = 266, \sigma = 16

1. What is the probability a randomly selected pregnancy lasts less than 260 days?

This is the p-value of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{260 -  266}{16}

Z = -0.375

Z = -0.375 has a p-value of 0.3539.

0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?

Now n = 20, so:

Z = \frac{X - \mu}{s}

Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}

Z = -1.68

Z = -1.68 has a p-value of 0.0465.

0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?

Now n = 50, so:

Z = \frac{X - \mu}{s}

Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}

Z = -2.65

Z = -2.65 has a p-value of 0.0040.

0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?

Sample of size 15 means that n = 15. This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.

X = 276

Z = \frac{X - \mu}{s}

Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}

Z = 2.42

Z = 2.42 has a p-value of 0.9922.

X = 256

Z = \frac{X - \mu}{s}

Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}

Z = -2.42

Z = -2.42 has a p-value of 0.0078.

0.9922 - 0.0078 = 0.9844

0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

8 0
2 years ago
A national appliance store chain is reviewing the
7nadin3 [17]

Answer:

d

Step-by-step explanation:

8 0
2 years ago
You can pay $10 for 2 movie tickets assuming the same rate , how much would you pay for 5 movie tickets ?
11Alexandr11 [23.1K]

Answer:

If we assume every 2 movie tickets is $10 then every one ticket would be $5. Assuming this to be true then 5 tickets is $25.

StepByStep Explanation:

movie tickets = t

2t=10

t=5

5t=?

5(5)=?

25=?

?=25


8 0
3 years ago
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
PLEASE HELP ASAP
Ahat [919]

Answer:

5x+32

Step-by-step explanation:

So write out as an expression

Amy= x

Baz = x+8

Carla = 3(x+8)

Total= x +x + 8 +3x+ 24

= 5x+32

8 0
2 years ago
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