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lukranit [14]
3 years ago
11

knowing the points a(1, 6), b(−5, −2), c(−1, −5), and d(5, 3), and that segment ab is parallel to segment cd, what is the length

of segment ab and segment cd comma and do points a, b, c, and d form a parallelogram? hint: to prove these points form a parallelogram, segment ab and segment cd must be equal in length
Mathematics
1 answer:
denpristay [2]3 years ago
8 0
Length of a line given two points is given by:
 l= 
\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}  \\ AB= \sqrt{(-5-1)^2+(-2-6)^2}  \\ = 
\sqrt{(-6)^2+(-8)^2}  \\ = \sqrt{36+64}  \\ = \sqrt{100}  \\ =10 \\  \\ 
CD= \sqrt{(3-(-5))^2+(5-(-1))^2}  \\ = \sqrt{(3+5)^2+(5+1)^2}  \\ = 
\sqrt{8^2+6^2}  \\ = \sqrt{64+36}  \\ = \sqrt{100}  \\ =10
Since |AB| = |CD|, points A, B, C, D form a parallelogram.
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The temperature of a certain solution is estimated by taking a large number of independent measurements and averaging them. The
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Answer:

(a) The 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b) The confidence level is 68%.

(c) The necessary assumption is that the population is normally distributed.

(d) The 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

Step-by-step explanation:

Let <em>X</em> = temperature of a certain solution.

The estimated mean temperature is, \bar x=37^{o}C.

The estimated standard deviation is, s=0.1^{o}C.

(a)

The general form of a (1 - <em>α</em>)% confidence interval is:

CI=SS\pm CV\times SD

Here,

SS = sample statistic

CV = critical value

SD = standard deviation

It is provided that a large number of independent measurements are taken to estimate the mean and standard deviation.

Since the sample size is large use a <em>z</em>-confidence interval.

The critical value of <em>z</em> for 95% confidence interval is:

z_{0.025}=1.96

Compute the confidence interval as follows:

CI=SS\pm CV\times SD\\=37\pm 1.96\times 0.1\\=37\pm0.196\\=(36.804, 37.196)\\\approx (36.80^{o}C, 37.20^{o}C)

Thus, the 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b)

The confidence interval is, 37 ± 0.1°C.

Comparing the confidence interval with the general form:

37\pm 0.1=SS\pm CV\times SD

The critical value is,

CV = 1

Compute the value of P (-1 < Z < 1) as follows:

P(-1

The percentage of <em>z</em>-distribution between -1 and 1 is, 68%.

Thus, the confidence level is 68%.

(c)

The confidence interval for population mean can be constructed using either the <em>z</em>-interval or <em>t</em>-interval.

If the sample selected is small and the standard deviation is estimated from the sample, then a <em>t</em>-interval will be used to construct the confidence interval.

But this will be possible only if we assume that the population from which the sample is selected is Normally distributed.

Thus, the necessary assumption is that the population is normally distributed.

(d)

For <em>n</em> = 10 compute a 95% confidence interval for the temperature as follows:

The (1 - <em>α</em>)% <em>t</em>-confidence interval is:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}

The critical value of <em>t</em> is:

t_{\alpha/2, (n-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table for the critical value.

The 95% confidence interval is:

CI=37\pm 2.262\times \frac{0.1}{\sqrt{10}}\\=37\pm 0.072\\=(36.928, 37.072)\\\approx (36.93^{o}C, 37.07^{o}C)

Thus, the 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

3 0
2 years ago
If the length of a rectangle is 5 m more than its width find the values of length and width if the area of a rectangle is 500 m²
astra-53 [7]

Answer:

Length of the rectangle  =25

width of the rectangle  = 20

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'x' be the width of the rectangle

Given that the length of a rectangle is 5 m more than its width

Given that Area of the rectangle = 500m²

length of a rectangle = x +5

width of a rectangle = x

<u><em>Step(ii):-</em></u>

Area of the rectangle = length × width

             500 = x ( x+5)

          x² + 5 x = 500

      ⇒  x² + 5 x - 500 =0

      ⇒  x² +25x - 20 x - 500 =0

    ⇒  x( x+25) -20(x+25) =0

  ⇒  (x-20)(x+25) =0

 ⇒  x =20 and x=-25

we can choose x =20

<u><em>Step(iii):-</em></u>

Length of the rectangle = x +5 = 20 +5 =25

width of the rectangle  = 20

<u><em>Final answer</em></u>:-

Length of the rectangle  =25

width of the rectangle  = 20

3 0
2 years ago
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