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frez [133]
3 years ago
8

Light travels 9.45 \cdot 10^{15}9.45⋅10 ​15 ​​ 9, point, 45, dot, 10, start superscript, 15, end superscript meters in a year. t

here are about 3.15 \cdot 10^73.15⋅10 ​7 ​​ 3, point, 15, dot, 10, start superscript, 7, end superscript seconds in a year. how far does light travel per second?
Mathematics
2 answers:
Anna [14]3 years ago
6 0

We are given that the distance light travel is:

9.45 x 10^15 meters / year

 

And that there is:

3.15 x 10^7 seconds / year

 

So the distance light travels per second is:

distance = (9.45 x 10^15 meters / year) * (1 year / 3.15 x 10^7 seconds)

<span>distance = 3 x 10^8 meters / second</span>

Arturiano [62]3 years ago
6 0

Answer:  3\times 10^8 meter per seconds

Step-by-step explanation:

In 1 year the distance traveled by light = 9.45\times 10^{15} meters,

\implies \text{1 year } = 9.45\times 10^{15}\text{ meters}

\text{Since, 1 years } = 3.15\times 10^7\text{ seconds}

\implies 3.15\times 10^7\text{ seconds} = 9.45\times 10^{15}\text{ meters}

\implies \text{ 1 seconds } = \frac{9.45\times 10^{15}}{3.15\times 10^7}\text{ meters}

\implies \text{ 1 seconds } =\frac{9.45}{3.15}\times 10^{15-7}

\implies \text{ 1 seconds} = 3\times 10^8\text{ meters}

Thus, light travels 3\times 10^8 meter in a second.

⇒ Its speed = 3\times 10^8 meter per seconds

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Put that value into either equation (now, which is easier?) to solve for x:

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