50 - [(6² - 24) + 9√25]
= 50 - [36 - 24 + 9*5]
= 50 - [12 + 45]
= 50 - 57
= -7
The answer is 1.25.
The equation for slope is rise over run. Y is the rise and X is the run. The point equation is (y2-y1)/(x2-x-1) = slope.
Plugging in the numbers: (-4-1)/(-4-0) = 1.25
So we're given Y = 3x.
We now can replace Y, for 3x in the equation:
Y = x + 4
3x = x + 4
3x - x = 4
2x = 4
x = 2
Answer:
![\frac{3}{16} \textrm{of the gargantuas will be unplanted}.](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B16%7D%20%5Ctextrm%7Bof%20the%20gargantuas%20will%20be%20unplanted%7D.)
Step-by-step explanation:
Given: Browns have planted 3/16 tomatoes, 1/4 cabbage and 3/8 peppers.
First lets find out the total fraction of planted.
![\frac{3}{16} +\frac{1}{4} +\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B16%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%2B%5Cfrac%7B3%7D%7B8%7D)
Now taking LCD for 16,4 and 8 to add up the fraction.
∴ LCD is 16
Next adding the fraction,
![\frac{3\times 1+1\times 4+ 3\times 2}{16} = \frac{13}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B3%5Ctimes%201%2B1%5Ctimes%204%2B%203%5Ctimes%202%7D%7B16%7D%20%3D%20%5Cfrac%7B13%7D%7B16%7D)
∴ Total fraction of planted gargantuas is ![\frac{13}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B16%7D)
Lets take the size of gragantuas as ``1``
∴ To find the un planted fraction of gargantuas.
![(1- \textrm{Total fraction of planted part of gargantuas})](https://tex.z-dn.net/?f=%281-%20%5Ctextrm%7BTotal%20fraction%20of%20planted%20part%20of%20gargantuas%7D%29)
=![1-\frac{13}{16}](https://tex.z-dn.net/?f=1-%5Cfrac%7B13%7D%7B16%7D)
=
∴ 3/16 is the unplanted fraction of gargantuas.
Answer:
473 milliliters.
Step-by-step explanation:
We have been given that there are 946 milliliters in a quart. There are 2 pints in a quart.
To find the number of milliliters in a pint we will divide 946 by 2.
![\text{Amount of milliliters in a pint}=473](https://tex.z-dn.net/?f=%5Ctext%7BAmount%20of%20milliliters%20in%20a%20pint%7D%3D473)
Therefore, there are 473 milliliters in one pint.