Answer:
cat
Step-by-step explanation:
This is based on understanding what dilation means in a graph transformation.
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<em>The dilation from first square directly to sixth square will be; (x,y) -> (243, 243)</em>
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- In transformations, dilation of an object involves producing an image of the object that is the same shape but not the same size.
This means that if we want to dilate a square, we will produce a bigger square of a different size.
- We are told one corner of the first square she drew is (2, 2). This means that one side of the square is 2 units as the four sides of a square are equal.
- For the second square, she dilates the first one using (x, y) -> (3x, 3y).
This means the corner that was (2, 2) will now be (3 × 2), (3 × 2) = (6, 6)
- For the third square, it will be; (3 × 6), (3 × 6) = (18, 18)
- For the fourth square, it will be; (3 × 18), (3 × 18) = (54, 54)
- For the fifth square, it will be; (3 × 54), (3 × 54) = (162, 162)
- For the sixth square, it will be; (3 × 162), (3 × 162) = (486, 486)
Since first square was (2, 2), then it means dilation from first square directly to sixth square will be; (x,y) -> (486/2, 486/2)
⇒ (x,y) -> (243, 243)
Read more at; brainly.com/question/2523916
Answer:
A: C = 15N
Step-by-step explanation:
30/2 = 15 (the cost of 1 class)
The area between the two functions is 0
<h3>How to determine the area?</h3>
The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
Read more about areas at:
brainly.com/question/14115342
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