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2 years ago

I NEED HELP ASAP BEFORE IT TIMES OUT!

Mathematics

2 answers:

padilas [110]2 years ago

7 0

Ahh ok so split it up into two rectangles:

Rectangle one:
A=lw
A=4(12)
A=48

Rectangle two:
A=lw
A=10(2)
A=20

Add both areas up to get 68 ft squared!! :)

pochemuha2 years ago

6 0

Answer:

68 square feet.

Step-by-step explanation:

My way of doing it is to first, split the shape where the length is different so it would be easier to solve. That means you should have the bottom part of the shape split from the whole shape, which makes 2 rectangles. The bottom rectangle should have the length of 2 feet, and the width of 10 feet on both parallel sides. The top rectangle should have the length of 4 feet, and the width of 12 feet on both parallel sides.

Next, you multiply both rectangles by their width and length. For example, first start with the first rectangle on the top. You should multiply the length, 4 feet by the width, 12 feet. Then, for the bottom rectangle, multiply the length, 2 feet by the width, 10 feet.

1.) 4 x 12 = 48

2) 2 x 10 = 20

Lastly, add the two numbers to get the answer.

48 + 20 = <u>68</u>

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14-12x+39x-18x=256-60x-657x

emmasim [6.3K]

Answer:

$\boxed{\bold{x=\frac{1}{3}}}$

Step-by-step explanation:

Combine Similar Elements: $\bold{-12x+39x-18x=9x}$

$\bold{14+9x=256-60x-657x}$

Combine Similar Elements: $\bold{-60x-657x=-717x}$

$\bold{14+9x=256-717x}$

Subtract 14 From Both Sides

$\bold{14+9x-14=256-717x-14}$

Simplify

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Add $\bold{717x}$ To Both Sides

$\bold{9x+717x=-717x+242+717x}$

Simplify

$\bold{726x=242}$

Divide Both Sides By $\bold{726}$

$\bold{\frac{726x}{726}=\frac{242}{726}}$

Simplify

$\bold{x=\frac{1}{3}}$

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3 years ago

Is -451 in the sequence below?<br> 15,7,-1,-9,,-17..

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Answer:

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Step-by-step explanation:

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2 years ago

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In the expression -12+m-9m+13, name the coefficients

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Answer:

-12

Step-by-step explanation:

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Solve for x in the equation 2x^2+3x-7=x^2+5x+39

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Hey there, hope I can help!

$\mathrm{Subtract\:}x^2+5x+39\mathrm{\:from\:both\:sides}$
$2x^2+3x-7-\left(x^2+5x+39\right)=x^2+5x+39-\left(x^2+5x+39\right)$

Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
$x^2-2x-46=0$

Lets use the quadratic formula now
$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$
$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:} a=1,\:b=-2,\:c=-46: x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-46\right)}}{2\cdot \:1}$

$\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \ \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ \frac{2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}$

Multiply the numbers 2 * 1 = 2
$\frac{2+\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}$

$2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \ \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ \sqrt{\left(-2\right)^2+1\cdot \:4\cdot \:46} \ \textgreater \ \left(-2\right)^2=2^2, 2^2 = 4$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1\cdot \:46=184 \ \textgreater \ \sqrt{4+184} \ \textgreater \ \sqrt{188} \ \textgreater \ 2 + \sqrt{188}$
$\frac{2+\sqrt{188}}{2} \ \textgreater \ Prime\;factorize\;188 \ \textgreater \ 2^2\cdot \:47 \ \textgreater \ \sqrt{2^2\cdot \:47}$

$\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \ \sqrt{47}\sqrt{2^2}$

$\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \ \sqrt{2^2}=2 \ \textgreater \ 2\sqrt{47} \ \textgreater \ \frac{2+2\sqrt{47}}{2}$

$Factor\;2+2\sqrt{47} \ \textgreater \ Rewrite\;as\;1\cdot \:2+2\sqrt{47}$
$\mathrm{Factor\:out\:common\:term\:}2 \ \textgreater \ 2\left(1+\sqrt{47}\right) \ \textgreater \ \frac{2\left(1+\sqrt{47}\right)}{2}$

$\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \ 1+\sqrt{47}$

Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.

$\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \ \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \ \frac{2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}$

$\frac{2-\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}$

$2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \ 2-\sqrt{188} \ \textgreater \ \frac{2-\sqrt{188}}{2}$

$\sqrt{188} = 2\sqrt{47} \ \textgreater \ \frac{2-2\sqrt{47}}{2}$

$2-2\sqrt{47} \ \textgreater \ 2\left(1-\sqrt{47}\right) \ \textgreater \ \frac{2\left(1-\sqrt{47}\right)}{2} \ \textgreater \ 1-\sqrt{47}$

Therefore our final solutions are
$x=1+\sqrt{47},\:x=1-\sqrt{47}$

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