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aleksandrvk [35]

3 years ago

11

Tyrone weighed 1 box of macaroni on a scale and found it weighed 0.6 pounds. What could Tyrone do to find the total weight of 10

0 boxes of macaroni?

2 answers:

ollegr [7]3 years ago

6 0

Answer:

He could multiply the amount one box ways by 100, or 0.6*100.

Step-by-step explanation:

larisa [96]3 years ago

4 0

He could times 0.6 by 100

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Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif

Novay_Z [31]

Answer: Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression : $6x^3-2x + 3$

Second expression : $-3x^3+5x^2+4x-7$ .

We need to subtract $6x^3-2x + 3$ from $-3x^3+5x^2+4x-7$ .

Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

$(-3x^3+5x^2+4x-7)+(-6x3+2x-3)$

Step 2: Removing parenthesis

$(-3x^3) +5x^2+4x + (-7) + (-6x^3) + 2x + (-3)$

Step 3: Grouping like terms

$[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]$

Step 4: Combing like terms

$-9x^3 + 6x + (-10) + 5x^2$

Step 5: Writing the final expression in standard form

$-9x^3 + 5x^2 + 6x-10$

8 0

3 years ago

Read 2 more answers

Marcus spent 10 hours doing his homework last week. This week he spent 11 hours doing homework. He says that he spent 110% more

swat32

Answer:

Yes he is correct, If it was 100% then it would stay the same 10 hours. But since it's 110%, it is in fact 11.

Step-by-step explanation:

7 0

3 years ago

Please help worth 20 points

almond37 [142]

Answer:

Try going on D.e.s.m.o.s.c.o.m it worked for me when I had something like this

Step-by-step explanation:

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2 years ago

Please help me find the answer pls

fiasKO [112]

Answer:

A. Solutions are: x = 2, y = 1.

B. Solutions are: x = 3, y = 2.

C.

1. Inconsistent

2. Inconsistent

3. Consistent

Step-by-step explanation:

A. Solutions of each system of linear equations by substitution method:

Equation 1: 3x - 2y = 4

Equation 2: x = 2y

<u>Step 1:</u> Substitute x = 2y into the Equation 1:

3(2y) - 2y = 4

6y - 2y = 4

4y = 4

Step 2: Divide both sides of the equation by 4 to isolate y:

$\frac{4y}{4} = \frac{4}{4}$

y = 1.

<u>Step 3:</u> For Equation 2, x = 2y, substitute y = 1 into the equation to solve for x:

x = 2y

x = 2(1)

x = 2

Therefore, the solutions are: x = 2, y = 1.

B. Find the solutions of each system of linear equations by elimination method:

Equation 1: 2x + y = 8

Equation 2: x + y = 5

<u>Step 1:</u> Multiply Equation 2 by 2:

2(x + y) = 5(2)

2x + 2y = 10

<u>Step 2:</u> Subtract Equation 1 from the equation derived from Step 1, 2x + 2y = 10:

2x + 2y = 10

- <u>2x + y = 8</u>

y = 2

Step 3: Plug in y = 2 into Equation 1, 2x + y = 8 to solve for x:

2x + y = 8

2x + (2) = 8

<u>Step 4:</u> subtract both sides of the equation by 2 to isolate x:

2x + 2 - 2 = 8 - 2

2x = 6

<u>Step 5:</u> Divide both sides of the equation by 2 to solve for x:

$\frac{2x}{2} = \frac{6}{2}$

x = 3.

The solutions are: x = 3, y = 2.

C:

1. Inconsistent

2. Inconsistent

3. Consistent (infinitely many solutions)

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3 years ago

Find the gcf of the terms of the polynomial. 44x^5 16x^3

julia-pushkina [17]

$44x^5=4x^3\cdot11x^2\\\\16x^3=4x^3\cdot4\\\\\boxed{GCF(44x^5;\ 16x^3)=4x^3}\to\fbox{c.}$

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3 years ago