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blondinia [14]
4 years ago
11

You collect a total of $75 in donations from three people. The three donations are in the ratio 4 : 4 : 7.

Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
4 0
<span>Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.</span>
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Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b
pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2, \sigma = 0.33

What is the minimum level for which the battery pack will be classified as highly sought-after class

At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 2}{0.33}

X - 2 = 0.33*1.28

X = 2.42

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

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3 years ago
HELP!!! <br> I’m The two triangles are similar. Solve for p.<br> Given an exact answer.<br> A<br> 16
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Answer: p = 14

Step-by-step explanation:

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3 years ago
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3 years ago
Givea)Possible number of positive real rootsb)Possible number of negative real rootsc)Possible rational roolsd)Find the roots
CaHeK987 [17]

The function is given to be:

x^3-2x^2-3x+6

QUESTION A

We can use Descartes' Rule of Signs to check the positive real roots of a polynomial.

The rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients, or is less than it by an even number.

If we have:

f(x)=x^3-2x^2-3x+6

The coefficients are: +1, -2, -3, +6.

We can see that there are only 2 sign changes; from the first to the second term, and from the third to the fourth term.

Therefore, there are 2 or 0 positive real roots.

QUESTION B

To find the number of negative real roots, evaluate f(-x) and check for sign changes:

\begin{gathered} f(-x)=(-x)^3-2(-x)^2-3(-x)+6 \\ f(-x)=-x-2x^2+3x+6 \end{gathered}

The coefficients are: -1, -2, +3, +6.

We can see that there is only one sign change; from the second term to the third term.

Therefore, there is 1 negative real root.

QUESTION C

To check the possible rational roots, we can use the Rational Root Theorem since all the coefficients are integers.

The Rational Root Theorem states that if the polynomial:

P(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_2x^2+a_1x+a_0

has any rational roots, they must be in the form:

\Rightarrow\pm\mleft\lbrace\frac{factors\text{ of }a_0}{factors\text{ of }a_n}\mright\rbrace

From the polynomial, the trailing coefficient is 6:

a_o=6

Factors of 6:

\Rightarrow\pm1,\pm2,\pm3,\pm6

The leading coefficient is 1:

a_n=1

Factors of 1:

\Rightarrow\pm1_{}

Write in the form

\Rightarrow\mleft\lbrace\frac{a_o}{a_n}\mright\rbrace

Therefore,

\Rightarrow\pm(\frac{1}{1}),\pm(\frac{2}{1}),\pm(\frac{3}{1}),\pm(\frac{6}{1})

Therefore, the possible rational roots are:

\Rightarrow\pm1,\pm2,\pm3,\pm6

QUESTION D

We can use a graph to check the roots of the polynomial. The graph is shown below:

The roots of the polynomial refer to the points when the graph intersects the x-axis.

Therefore, the roots of the polynomial are:

x=-1.732,x=1.732,x=2

7 0
2 years ago
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