Answer: 7 students
Step-by-step explanation:
From the question, we are informed that there a camp is divided into2 groups and that there are 14 kids in Camp A and 21 kids in Camp B.
If the camps are divided into groups of equal size, there will be 7 students in a group. This will be gotten from :
Camp A = 14/2 = 7 students
Camp B = 21/3 = 7 students
Answer:

Step-by-step explanation:
Given :-
The sum of two numbers is 1 .
The product of the nos . is 12 .
And we need to find out the numbers. So let us take ,
First number be x
Second number be 1-x .
According to first condition :-

Hence the numbers are 4 and -3
Answer:
Step-by-step explanation:
Surface area of objects with flat surfaces like this is simply the area of each surface added together, so let's get to work.
Both have 6 faces, so we will be adding six values together for each.
Container A:
Hopefully you can imagine the six different faces. It's kinda like a cereal box.
The front and back of a cereal box have the same area, as do the two sides and the top and bottom, so that makes it a little easier.
Front and Back: 28 * 36 = 1008
Sides: 36*6 = 216
Top and Bottom: 6*28 = 168
Let me know if you don't understand how I did any of that. Anyway, since there is a matching face for each we add them all together twice.
1008*2 + 216*2 + 168*2 = 2784 in^2
Container B has a similar setup, I won't write out everything like I did unless you want me to work it out with you.
2(16*12+16*22+22*12) = 1616 in^2
So since Container A has a surface area of 2784 and Container B has a surface area of 1616 it's obvious container A has a larger surface area
Answer:
We need to find the area of the semicircles + the area of the square.
The area of a square is equal to the square of the lenght of one side.
As = L^2 = 58m^2 = 3,364 m^2
Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:
Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2
And the area of a semicircle is half of that, so the area of each semicircle is:
a = (2,289.06m^2)/2 = 1,144.53m^2
And we have 4 of those, so the total area of the semicircles is:
4*a = 4* 1,144.53m^2 = 4578.12m^2
Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2
This is nothing like the provided anwer of Val, so the numbers of val may be wrong.