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love history [14]
3 years ago
10

Which property is demonstrated in the equation below? a • 0 = 0 additive identity multiplicative identity multiplicative propert

y of zero commutative property of multiplication
Mathematics
1 answer:
Svetllana [295]3 years ago
5 0
Zero commutative<span>property of multiplication. </span>The zero commutative property of multiplication states that when any number is multiplied by 0 the result is always zero
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Iteru [2.4K]

Answer:

1: 18    2:18    3:18

Step-by-step explanation:

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What percent of a data set is represented by Q1
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If Joan read 75 pages in 4 hours how long will it take her to read 250 pages
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Write a declaration for a variable rate_of_pay that can hold values like 11.50 or 12.75.
hichkok12 [17]

Float rate_of_pay  a declaration for a variable rate_of_pay that can hold values like 11.50 or 12.75.

What is   float rate_of_pay?

  • In contrast to fixed (or unchangeable) interest rates, floating interest rates change on a regular basis. Companies that offer credit cards and mortgages frequently use floating rates.
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Is a fixed or floating rate preferable?

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rate_of_pay = 11.50, 12.75;

Learn more about Float rate_of_pay

brainly.com/question/14128610

#SPJ4

7 0
1 year ago
Given the function f(x) = 4(2)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Dmitry [639]

Answer:

Step-by-step explanation:

I'm sure you want your functions to appear as perfectly formed as possible so that others can help you.  f(x) = 4(2)x should be written with the " ^ " sign to denote exponentation:  f(x) = 4(2)^x

                                                                                      f(b) - f(a)

The formula for "average rate of change" is a.r.c. = --------------

                                                                                           b - a

                                    change in function value

This is equivalent to  ---------------------------------------

                                            change in x value

For Section A:  x changes from 1 to 2 and the function changes from 4(2)^1 to  4(2)^2:  8 to 16.  Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2.  Thus, in this Section, the a.r.c. is:

                 8

               ------ = 8 units    (Section A)

                  1

Section B:  x changes from 3 to 4, a net change of 1 unit:  f(x) changes from

4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units.  Thus, the a.r.c. is

        224 units

      ----------------- = 224 units (Section B)

            1 unit

The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.

This change in outcome is so great because the function f(x) is an exponential function; as x increases in unit steps, the function increases much faster (we say "exponentially").

7 0
3 years ago
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