S = b + 15
s = skirt
b = blouse
The skirt is $15 more than the blouse
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
Step-by-step explanation:
Option B 2. Now is the correct answer because when we multiply 6 by 2 we get 12 then we multiply 12 by 2 we get 24
First of all, it is a ratio. I know that for a fact, but not very sure about the candy part. What I think it means is that they are comparing two types of candy.
