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2 years ago

Which graph represents the inequality x greater-than 6?

Mathematics

2 answers:

ludmilkaskok [199]2 years ago

6 0

Answer:

Step-by-step explanation:

Because it isn't a negative number so it should have a closed circle with a line going to 11 and on. Hoped this helped. ;)

scoundrel [369]2 years ago

5 0

Answer:

Step-by-step explanation:

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Equation:y=5/3x+5<br> Slope:5/3<br> y-intercept:?

Anettt [7]

The y intercept will be 5

4 0

3 years ago

Read 2 more answers

Perform the operation. Enter your answer in scientific notation.<br> (7 x 10^*9)(5.6 x 10^*8)

Zinaida [17]

Answer:

3.92 × 10 ^18

Step-by-step explanation:

(7 x 10^*9)(5.6 x 10^*8)

(7000000000)(560000000)

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

If the decimal is moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

3 0

3 years ago

What does this equation equal?<br> 4-2(-2)=

olga_2 [115]

Answer:

Step-by-step explanation:

Pemdas:

4-2(-2)

4+4

Hope this helped!

6 0

3 years ago

ONLY answer if you know what the answer is. If you are not sure DONT FREAKING ANSWER.

Bogdan [553]

Answer:

5 = |-5|

Step-by-step explanation:

Think of it as a number line, like in the picture below. The absolute value is how far a number is from zero (0). If 5 is 5 away from zero, then the opposite of 5 (-5) is also 5 away from zero.

Refer to the picture below for an illustration:

8 0

2 years ago

Read 2 more answers

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago