Given that the concentration has been modeled by the formula:
C(t)=50t/(t^2+25)
where:
t is time in hours.
The concentration after 5 hours will be given by:
t= 5 hours
plugging the value in the equation we get:
C(5)=(50(5))/(5^2+25)
simplifying the above we get:
C(5)=250/(50)=5 mg/dl
Answer: 5 mg/dl
Answer:
The required probability is 0.533.
Step-by-step explanation:
Consider the provided information.
The actual weight of the chocolate has a uniform distribution ranging from 31 to 32.5 ounces.
Let x is the random variable for the actual weight of chocolate.
According to PDF function.

Where 
It is given that ranging from 31 to 32.5 ounces.
Substitute a=31 and b=32.5 in above function.


We need to find the probability that a box weighs less than 31.8 ounces
Now according to PDF:


Hence, the required probability is 0.533.
Answer:
762.08.
Step-by-step explanation:
952.60x0.20=190.52
952.60-190.52=762.08
Answer:
zeros : -3/2 , multiplicity = 1
1 , multiplicity = 2
Step-by-step explanation:

To find zeros we set each factor =0 and solve for x
2x+3 =0
subtract 3 on both sides
2x= -3
divide by 2 on both sides
x= -3/2
The exponent of (2x+3) is 1 so multiplicity =1
Now we set (x-1)^2 =0
take square root on both sides
x-1 =0
add 1 on both sides
x=1
For (x-1)^2 the exponent is 2
So multiplicity = 2