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Rainbow [258]
3 years ago
7

Why did Euler enter the Paris Academy of Sciences Prize Problem competition ?

Mathematics
2 answers:
anzhelika [568]3 years ago
6 0
He wanted the mathematical challenge
nalin [4]3 years ago
6 0

Answer:He wanted the mathematical challenge

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The concentration C (in mg/dl), of a certain antibiotic in a patient's bloodstream is given by C(t)=50 t /(t^2 + 25) where t is
marishachu [46]
Given that the concentration has been modeled by the formula:
C(t)=50t/(t^2+25)
where:
t is time in hours.
The concentration after 5 hours will be given by:
t= 5 hours 
plugging the value in the equation we get:
C(5)=(50(5))/(5^2+25)
simplifying the above we get:
C(5)=250/(50)=5 mg/dl

Answer: 5 mg/dl
8 0
2 years ago
Delicious Candy markets a two-pound box of assorted chocolates. Because of imperfec- tions in the candy making equipment, the ac
saveliy_v [14]

Answer:

The required probability is 0.533.

Step-by-step explanation:

Consider the provided information.

The actual weight of the chocolate has a uniform distribution ranging from 31 to 32.5 ounces.

Let x is the random variable for the actual weight of chocolate.

According to PDF function.

P(a\leq x\leq b)=\int\limits^b_a {f(x)} \, dx

Where f(x)=\left\{\begin{matrix}\frac{1}{b-a} & a

It is given that ranging from 31 to 32.5 ounces.

Substitute a=31 and b=32.5 in above function.

f(x)=\left\{\begin{matrix}\frac{1}{32.5-31} & 31

f(x)=\left\{\begin{matrix}\frac{1}{1.5} & 31

We need to find the probability that a box weighs less than 31.8 ounces

Now according to PDF:

P(x

P(x

Hence, the required probability is 0.533.

6 0
3 years ago
600,000+80,000+10 in a form
Nezavi [6.7K]
680,010 is the answer
7 0
3 years ago
Read 2 more answers
A store advertises a 20% markdown on a dishwasher that normally sells for $952 find the sale price
CaHeK987 [17]

Answer:

762.08.

Step-by-step explanation:

952.60x0.20=190.52

952.60-190.52=762.08

6 0
3 years ago
Read 2 more answers
Find zeroes and multiplicity for y=(2x +3)(x -1)^2
muminat

Answer:

zeros : -3/2 , multiplicity = 1

1 , multiplicity = 2

Step-by-step explanation:

y=(2x +3)(x -1)^2

To find zeros we set each factor =0  and solve for x

2x+3 =0

subtract 3 on both sides

2x= -3

divide by 2 on both sides

x= -3/2

The exponent of (2x+3) is 1 so multiplicity =1

Now we set (x-1)^2 =0

take square root on both sides

x-1 =0

add 1 on both sides

x=1

For (x-1)^2  the exponent is 2

So multiplicity = 2


7 0
3 years ago
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