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Rainbow [258]
3 years ago
7

Why did Euler enter the Paris Academy of Sciences Prize Problem competition ?

Mathematics
2 answers:
anzhelika [568]3 years ago
6 0
He wanted the mathematical challenge
nalin [4]3 years ago
6 0

Answer:He wanted the mathematical challenge

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Under her cell phone plan, Autumn pays a flat cost of $48 per month and $5 per gigabyte. She wants to keep her bill at $68.50 pe
VikaD [51]

Answer:

4 gigabytes

Step-by-step explanation:

Equation: 68.50=48+5x

8 0
2 years ago
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A pile of earth removed from an excavation is a cone measuring 6ft high and 30ft across its base. How many trips will it take to
nignag [31]

Answer: 14

Step-by-step explanation:

Given

Excavation cone measures

height h=6\ ft

Diameter d=30\ ft

Truck can dump 125\ ft^3 at a time

The volume of a cone is

V=\dfrac{1}{3}\pi r^2h

Putting values

\Rightarrow V=\dfrac{1}{3}\times \pi\times 15^2\times 6\\\Rightarrow V=1413.9\approx 1414\ ft^3

No of trips(N) required to accumulate this much volume is given by

\Rightarrow N=\dfrac{1414}{125}=13.3\approx 14

Therefore, 14 trips are necessary to accumulate a cone of volume 1414\ ft^3

8 0
3 years ago
Factorise the following 27 x minus 9 y​
dangina [55]

Answer:

27x-9y

3(9x-3y)

Step-by-step explanation:

please mark me as brainlest

4 0
2 years ago
HELP!?! PLEASE!! Which pair of fractions shows 7/9 and 5/12 correctly converted with their least common denominator?
svlad2 [7]
Least\ common\ denominator:\\\\\frac{7}{9}\ \ \ \frac{5}{12}\ \ we\ need\ to\ find\ number\ which\ can\ be\ divided\ by\ 12\ and\ 9\\\\\frac{7\cdot4}{9\cdot4}\ \ \ \frac{5\cdot3}{12\cdot3}\\\\\frac{28}{36}\ \ \ \frac{15}{36}\\\\Answer\ A.
5 0
3 years ago
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Rearrange w= 3(2a + b) - 4 to make a the subject
Angelina_Jolie [31]

Answer:

\boxed{a =  \frac{w}{ 6}  -  \frac{b}{2}  +  \frac{2}{3} }

Step-by-step explanation:

Solve  \: for \:  a:  \\  =  > w=3(2a+b)-4  \\  \\ w=3(2a+b)4 \: is \: equivalent \: to \: 3(2a+b)-4= w:  \\  =  > 3(2a+b) - 4=w  \\  \\ Expand \:  out \:  terms \:  of  \: the  \: left  \: hand \:  side:  \\  =  > (3 \times 2a) + (3 \times b) - 4 = w \\  =  > 6a+3b - 4=w  \\  \\ Subtract  \: 3b  - 4 \:  from  \: both \:  sides:  \\  =  >   6a + 3b - 4 - (3b - 4)=w - (3b - 4) \\   =  > 6a = w - 3b + 4 \\  \\ Divide  \: both  \: sides \:  by  \: 6: \\  =  >  \frac{ \cancel{6}a}{ \cancel{6}}  =  \frac{w - 3b + 4}{6}  \\   =  > a =  \frac{w}{6}  -  \frac{3b}{6}  +  \frac{4}{6}  \\  =  > a =  \frac{w}{ 6}  -  \frac{b}{2}  +  \frac{2}{3}

8 0
3 years ago
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