Solve -2x^2 + 10x + 9 =0 by using completing the squares and give u r answer to two decimal places
2 answers:
<span>-2x^2 + 10x + 9 =0 multiply whole equation by -1 2x^2 -10x -9 =0 (sqrt2x)^2 -2(sqrt2x)(5/</span>sqrt2) -9=0 add (5/sqrt2)^2 on both sides (sqrt2x)^2 -2(sqrt2x)(5/sqrt2) + (5/sqrt2)^2-9=(5/sqrt2)^2 a^2-2ab+b^2=(a-b)^2 (sqrt2x - 5/sqrt2)^2=(5/sqrt2)^2+9 (sqrt2x - 5/sqrt2)^2=21.5 taking squareroot on both sides sqrt2x - 5/sqrt2 = +-4.64 so sqrt2x - 5/sqrt2 = +4.64 or sqrt2x - 5/sqrt2 = -4.64 sqrt2x = 4.64 + 5/sqrt2 sqrt2x = -4.64 + 5/sqrt2 sqrt2x =8.18 sqrt2x = -1.1045 x=8.18/sqrt2 x= -1.1045/sqrt2x=5.78 x=-0.781
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