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coldgirl [10]
3 years ago
13

Can someone help me with these

Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

5) 3x - 10 = x + 4

answer: 7

6) 6x + 4 = x - 11

answer: -3

Step-by-step explanation:

3x - 10 = x + 4

x = 7

6x + 4 = x - 11

x = -3

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A city manager made a scatter plot of the number or retail store in a certain city over the years. the scatter plot had a trend
Fiesta28 [93]

Answer:

155

Step-by-step explanation:

The problem sounds complicated, but it's not. Let's analyse.

The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.

We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.

Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).

In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.

y= 11x + 12

=> In Tracy's case: y= 11*13 + 12= 155

So the number of retail stores there were in 2003 was 155

5 0
3 years ago
Use long division:<br> 3x2 + 2x-5<br> 3x-1
uysha [10]
This is the answer just open it.

5 0
3 years ago
Read 2 more answers
A computer programming team has 17 members. (a) How many ways can a group of nine be chosen to work on a project? As in Example
Natali5045456 [20]

The number of groups that can be chosen from the team of 17 depends on the given conditions of the selection.

The correct responses are;

(a) The number of ways of choosing groups of 9 from the 17 members are 24,310 ways.

(b) (i) The number of groups of 9 containing 5 women and 4 men are 8,820 groups.

(ii) The number of groups of 9 that contain at least one man is 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) If two team members refuse to work together on projects, the number of groups of 9 that can be chosen are 17,875 groups.

(d) If two team members must work together or not at all the number of groups of 9 that can be chosen are 1,430 groups.

Given,

The combination of n objects taking r at a time is given as follows

ₙCr = (ⁿr)

(a) The number of ways of choosing groups of 9 from the 17 members is given as follows;

Number of ways of choosing groups of 9 = (17, 9)  = 24,310 ways.

(b) (i) Number of women = 9

Number of men = 8

Number of groups of 9 containing 5 women and 4 men = (9, 5) x (8, 4)

(9, 5) x (8, 4) = 126 x 70 = 8820

Number of groups of 9 containing 5 women and 4 men = 8,820 groups.

(ii) The number of groups that contain at least one man is (17, 9) - (9, 9)

(17, 9) - (9, 9) = 24,310 - 1 = 24,309

The number of groups that contain at least one man are 24,309 groups.

(iii) The number of groups of 9 that contain at most 3 women if given as follows;

(8, 8) × (9, 1) + (8, 7) × (9, 2) + (8, 6) × (9, 3) = 2649

The number of groups of 9 that contain at most 3 women are 2,649 groups.

(c) Given that two team members refuse to work together on projects, the number of groups of 9 that can be chosen are (15, 9) + 2 × (15, 8)

(15, 9) + 2 × (15, 8) = 5,005 + 2 × 6,435 = 17,875

(d) Two team members must work together or not at all is (15, 7) - (15, 9)

(15, 7) - (15, 9) = 6,435 - 5,005 = 1,430

The number of groups of 9 that can be chosen two team members must work together or not at all are 1,430 groups.

Learn more about number of ways here;

brainly.com/question/25310371

#SPJ4

7 0
1 year ago
ABLE Trucking Company has a job moving 21 tons of sand. The company has 8 drivers in the company and 2 types of trucks. One type
Feliz [49]
You need 3 trucks of sand that hold 5 tons and 2 trucks that hold 3 tons to move all the sand in one trip
8 0
3 years ago
Read 2 more answers
Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected
Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}

Hence, in our case

\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)

Transform points N, M, and O accordingly,

\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}<h2>Therefore, the answer is the first option (top to bottom)</h2>

6 0
1 year ago
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