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3 years ago

At 7:00 a.m., the temperature in Belleville, Ontario was -4°C. The

Mathematics

1 answer:

pychu [463]3 years ago

8 0

1°C is the temperature at noon.

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What is the value of p for they following triangular prism<br><br> Please help me!!!!!!!!!!!

viktelen [127]

If your only solving for the perimeter, then the answer is 18yd.

3 0

3 years ago

Find the equation of the sphere passing through P(negative 4 comma 7 comma 6 )and Q(8 comma negative 3 comma 5 )with its center

Juli2301 [7.4K]

Answer: The equation of the sphere is:

(x-2)^2 + (y-2)^2 + (z-5/2)^2 = sqrt(245)/2

Step-by-step explanation:

The centre of the sphere is the midpoint of the diameter, which is

1/2

[(-4,7,6) + (8,-3,5)] =(2,2,5/2)

The length of the diameter is

=sqrt |(8,-3,5) - (-4,7,6)|^2

=sqrt (12^2 + (-10)^2 + (-1)^2)

=sqrt (144+100+1)

=sqrt(245)

so the radius of

the sphere is:

1/2(sqrt(245)) = sqrt(245)/2.

The equation of the sphere is:

(x-2)^2 + (y-2)^2 + (z-5/2)^2 = sqrt(245)/2

4 0

3 years ago

ILL GIVE YOU BRAINLEST IF RIGHT

DanielleElmas [232]

Answer:

The total length of the pathway now is 1,541 ft

Step-by-step explanation:

To calculate the length of the pathway now, what we need to do is to have a consistency in units.

Thus, we need to convert the 513 yards to ft

Mathematically 1 yard = 3 feet

Thus 513 yards will be = 513 * 3 = 1,539 ft

Thus the total length of the pathway now will be 1539 ft + 2 ft = 1541 ft

3 0

2 years ago

Read 2 more answers

A rectangular prism has a length of 4.2 cm, a width of 5.8 cm, and a height of 9.6 cm. A similar prism has a length of 14.7 cm,

solong [7]

They are each multiplied by a factor of 3.5
You can calculate this by taking the length of the similar prism and divide it with the first prism 14.7/4.2 = 3.5
Do this with the width and height to be sure
20.3/5.8 = 3.5
33.6/9.6 = 3.5

5 0

3 years ago

Read 2 more answers

Last winter, the ratio of days with snow to day with no snow was 1.18. Write this ratio as a faction in simplest form

Alekssandra [29.7K]

to change any decimal to a fraction, we simply <u>use as many zeros on the denominator as there are decimals and lose the dot</u>.

1.18 has two decimals, so we'll use two zeros at the bottom, and lose the dot.

$\bf 1.\underline{18}\implies \cfrac{118}{1\underline{00}}\implies \stackrel{simplified}{\cfrac{59}{50}}$

6 0

3 years ago