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UNO [17]
3 years ago
13

Need some one to slove

Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0
The answers are 2 and 5 
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Which points in the scatter plot are outliers?
Tom [10]
Point F and point D are your answers.
5 0
3 years ago
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The weights of bags of ready-to-eat salad are normally distributed with a mean of 300 grams and a standard deviation of 9 grams.
mestny [16]

Answer: 2.5% of the bags weigh less than 282 grams.

Step-by-step explanation: Just took the test and this was the correct answer! :)

8 0
3 years ago
Cual es el coeficiente de variacion de los resultados de 30,60,90,45?
alexdok [17]

based on the given results, the coefficient of variation can be found to be 45.54.

<h3>what is the coefficient of variation?</h3>

first, find the mean:
= (30 + 60 + 90 + 45) / 4

= 56.25

find the standard deviation using a spreadsheet:

= 25.61737691

the coefficient of variation is therefore:

= standard deviation / mean x 100

= 25.61737691 / 56.25 x 100

= 45.54

find out more on the coefficient of variation at brainly.com/question/13293164.

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8 0
2 years ago
Hyxetdryufgukhchfxrdtygujhftyuhuhyguhjygyu
nikklg [1K]

Answer:

so the answer is: eijieljnqwsmiqwmx

did i answer it correctly let me know

Step-by-step explanation:

Destroy your keyboard by smashing each random word on the poor broken keyboard  

6 0
3 years ago
Read 2 more answers
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

7 0
3 years ago
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