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larisa86 [58]
3 years ago
7

Simplify − 11 50 (1.32 + 0.48). Give your answer as a decimal. − 11 50 (1.32 + 0.48) − 11 50 (1.8) −0.22(1.8)

Mathematics
2 answers:
vekshin13 years ago
8 0

Answer:

-.396

Step-by-step explanation:

deff fn [24]3 years ago
4 0

Given expression: − 11.50 (1.32 + 0.48).

We need to simplify it and get the answer in decimals.

Note: In order to simplify above given expression, we need to apply order to operations.

According to order to operations, we need to simplify parenthesis first.

So, we need to add 1.32 + 0.48 first.

1.32 + 0.48 = 1.80.

So, − 11.50 (1.32 + 0.48) would become -11.50(1.80).

Now, we need to multiply -11.50 by 1.80.

-11.50(1.80) = -20.7.

<h3>Therefore, final answer is -20.7.</h3>
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3 years ago
Solve for x, 5-x/3=-15
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8 0
3 years ago
A motorist took 1.2 hour to travel 96 km how far will he travel in 1 hour
miskamm [114]

Answer:

80km

Step-by-step explanation:

To solve this problem, we need to cross multiply. Lets input the values (1.2, 1.0, 96) as shown below:

\frac{1.2}{96} = \frac{1.0}{x}

Next we cross multiply. We multiply 1.2 and x, and we multiply 96 and 1.0.

1.2(x) = 1.2x

96 x 1.0 = 96

Now, lets put the values above back into the equation:

1.2x = 96

Lets solve this equation. First we divide 96 by 1.2.

1. x = \frac{96}{1.2}

2. x = 80

This means that our answer is 80km.

4 0
2 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
Which expression is equivalent to (f + g)(4)?
ddd [48]

(f + g)(x) = f(x) + g(x) therefore (f + g)(4) = f(4) + g(4)

3 0
2 years ago
Read 2 more answers
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