Answer:
Solution given:
x^3 - 2x^2 -x+2
take common from two each term
x²(x-2)-1(x-2)
take common again and keep left one on other bracket
<u>(x-2)(x²-1) or (x-1)(x+1)(x-2)</u> is a required answer.
note:using formula a²-b²=(a+b)(a-b) for x²-1.
Answer:
1/15
Step-by-step explanation:
2/5-1/3=6/15-5/15=1/15

To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Constant is occurring continuously over a period of time so C is the correct answer because C is constant for a period of time
Answer:
y° = 7°
Step-by-step explanation:
(8y +4) +(8y +4) +(8y +4)=180° ( Equilateral Triangle)
24y +12= 180°
24y= 180-12
y=7°