Answer:
The Bay of Pigs invasion
Explanation:
The Bay of Pigs invasion was an attempt of Cuban exiles to destroy the government of Fidel Castro. These were actions of the USA aimed against Cuba. This invasion was one unsuccessful try and shame for the regime of Kenedy. This was an example of a group decision that was unsuccessful. Ths attempt provoked many side effects, as entering of Cuban-Americans in the Congress of America.
<span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant.
O is always ii
A is IAi (heterozygous) or IAIA (homozygous)
B is IBi (heterozygous) or IBIB (homozygous)
AB is always IAIB
Remember: You get one allele from each parent!
1. Father must be ii, mother must be ii, so all children must be ii.
2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother.
3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes.
4. Father is ii, mother is IAIB. Children can only be IAi or IBi.
5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB.
Example of Punnett square:
3. Father is type A, heterozygous, mother is type B, heterozygous
Father must be IAi (heterozygous)
Mother must be IBi (heterozygous)
_______IA ____ i
IB____ IBIA____IBi
i _____ IAi______ii
Sorry, that was difficult on here, hope it's understandable.
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case.
Hope that helps!</span>
Its more natural and doesn't have side effects
According to Bronsted-Lowry acid concept
an acid is a that donate a proton" and a base is a "proton acceptor."so
will look for that molecule to which <span>H2O</span> "donates" H+to become <span>OH−</span>. so answer will be..
. <span>NH3+H2O→NH+4+O<span>H<span>−
so correct option is NH3
hope it helps</span></span></span>
