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2 years ago

If the radius of the circle is 12 inches, the area of the sector contained by the minor arc and two radii is what?

Mathematics

1 answer:

earnstyle [38]2 years ago

8 0

Answer:

113.14 Inches²

Step-by-step explanation:

The area of a sector A contain by the minor arc of a circle is given as

A = Ф°/360 * πr²

Where Ф is the angle formed in the arc, π is a constant given as 22/7 and r is the radius of the circle.

Given that the minor arc is contained by two radii, the angel between them is 90° hence, the area of the arc

= 90/360 * 22/7 * 12²

= 113.14 Inches²

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Answer:

$2.85

Step-by-step explanation:

The price Ellen pays can be found using the proportion ...

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Multiplying by 24 oz, we get ...

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2 years ago

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

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$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

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